Answer:
20.49 maybe?
Step-by-step explanation:
Answer:
Monica spent 0.55 hours listening to Brahms.
Step-by-step explanation:
We are given the following in the question:
Amount of time spent listening to tapes of Beethoven and Brahms =
Amount of time spent listening to Beethoven =
Total time spent listening to Brahms =
Amount of time spent listening to tapes of Beethoven and Brahms - Amount of time spent listening to Beethoven
Thus, Monica spent 
listening to Brahms.
Answer:
The solution in the attached figure
One possible solution is the point (30,60)
Step-by-step explanation:
Let
x -----> represents the number of tacos sold
y -----> represents the number of burritos sold
we know that
------> inequality A
-----> inequality B
using a graphing tool
The solution is the triangular shaded area
see the attached figure
One possible solution is the point (30,60)
Remember that if a ordered pair is a solution of the system of inequalities, then the ordered pair must lie on the shaded area of the solution
so
That means----> The number of tacos sold is 30 and the number of burritos sold
Verify
Substitute the value of x and the value of y in each inequality
Inequality A
----> is true
Inequality B
----> is true
The ordered pair satisfy both inequalities, then the ordered pair is a solution of the system
Read more on Brainly.com - brainly.com/question/13301815#readmore
Step-by-step explanation:
Answer:
Step-by-step explanation:
In the model
Log (salary) = B0 + B1LSAT +B2GPA +B3log(libvol) +B4log(cost)+B5 rank+u
The hypothesis that rank has no effect on log (salary) is H0:B5 = 0. The estimated equation (now with standard errors) is
Log (salary) = 8.34 + .0047 LSAT + .248 GPA + .095 log(libvol)
(0.53) (.0040) (.090) (.033)
+ .038 log(cost) – .0033 rank
(.032) (.0003)
n = 136, R2 = .842.
The t statistic on rank is –11(i.e. 0.0033/0.0003), which is very significant. If rank decreases by 10 (which is a move up for a law school), median starting salary is predicted to increase by about 3.3%.
(ii) LSAT is not statistically significant (t statistic ≈1.18) but GPA is very significance (t statistic ≈2.76). The test for joint significance is moot given that GPA is so significant, but for completeness the F statistic is about 9.95 (with 2 and 130 df) and p-value ≈.0001.
