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sattari [20]
4 years ago
15

A polynomial has zeros of 7, 6. What is the minimum degree of the polynomial?

Mathematics
1 answer:
Naddik [55]4 years ago
4 0
If the polynomial has zeros at 7 and 6 the equation will be
(X-7)(x-6)
When we distribute that we get
x^2-13x+42

A degree is the highest exponent of a polynomial. In this case the x^2. So the answer is 2
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Round to the nearest tenth
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Step-by-step explanation:

6 0
3 years ago
Find sin 2x, cos 2x, and tan 2x from the given information.<br> cscx=4,tanx&lt;0.
lutik1710 [3]

Answer:

Step-by-step explanation:

Given the expression cosec (x) = 4 and tan(x)< 0

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From SOH, CAH TOA

sinθ = opposite/hypotenuse

from sinx = 1/4

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to get the adjacent, we will use the Pythagoras theorem

adj² = 4²-1²

adj² = 16-1

adj ²= 15

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since tan < 0, then tanx = -1/√15

From double angle formula;

sin2x = 2sinxcosx

sin2x = 2(1/4)(√15/4)

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sin2x = √15/8

for cos2x;

cos2x = 1-2sin²x

cos2x = 1-2(1/4)²

cos2x = 1-2(1/16)

cos2x= 1-1/8

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for tan2x;

tan2x  = tanx + tanx/1-tan²x

tan2x = 2tanx/1-tan²x

tan2x = 2(-1/√15)/1-(-1/√15)²

tan2x = (-2/√15)/(1-1/15)

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tan2x = -2/√15 * 15/14

tan2x = -30/14√15

tan2x = -30/7√15

rationalize

tan2x =  -30/7√15 * √15/√15

tan2x =  -30√15/7*15

tan2x =  -2√15/7

5 0
3 years ago
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djyliett [7]

Answer: She should sell each T-Shirt for at least $4.41

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This should help you:


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