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sattari [20]
3 years ago
15

A polynomial has zeros of 7, 6. What is the minimum degree of the polynomial?

Mathematics
1 answer:
Naddik [55]3 years ago
4 0
If the polynomial has zeros at 7 and 6 the equation will be
(X-7)(x-6)
When we distribute that we get
x^2-13x+42

A degree is the highest exponent of a polynomial. In this case the x^2. So the answer is 2
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Find the equation of the line that passes through point A (1,7) and B (-3, -1)
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Answer:

The equation of the line is 2 x - y + 5 = 0.

Step-by-step explanation:

Here the given points are A( 1, 7) & B( -3, - 1) -

Equation of a line whose points are given such that

( x_{1}, y_{1} ) & ( x_{2}, y_{2} )-

 y - y_{1}  = \frac{ y_{2} - y_{1} }{ x_{2} - x_{1} }   ( x - x_{1}  )

i.e. <em> y - 7= \frac{- 1 - 7}{ -3-1}  ( x- 1)</em>

<em>       y - 7 =  \frac{- 8}{- 4} ( x -1)</em>

<em>       y - 7 =  2 ( x - 1) </em>

<em>       y - 7  =   2  x - 2</em>

<em>       2 x - y + 5 = 0</em>

Hence the equation of the required line whose passes trough the points ( 1, 7) & ( -3, -1)  is 2 x - y  + 5 = 0.

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3 years ago
Algebra question(s), please help!!!!
Angelina_Jolie [31]

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Hence, x ≈ 0.77m.

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3 years ago
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