The kinetic energy of the air travelling at 20m/s, which passes through
the circular area in 1 second is 5.4 x 10⁵ J.
What is kinetic energy?
The kinetic energy of an object is associated with its motion. It can be related to the mass and velocity as
K.E = 1/2 mv²
Given the wind is blowing directly towards the wind turbine at a speed of 20 m/s. At this wind speed, 7500 kg of air passes every second through the circular area swept out by the blades.
Substitute the values, we have
K.E = 1/2 x 7500 x (20)²
K.E = 15 x 10⁵ J
Hence, the kinetic energy of the air travelling at 20m/s, which passes through the circular area is 15 x 10⁵ J.
To know more about kinetic energy, refer: brainly.com/question/12669551
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<u><em>[NOTE: THIS IS AN INCOMPLETE QUESTION. THE CMPLETE QUESTION IS: the wind is blowing directly towards the wind turbine at a speed of 12 m/s. at this wind speed, 7500 kg of air passes every second through the circular area swept out by the blades. Calculate the kinetic energy of the air travelling at 12m/s, which passes through the circular area in 1 second.]</em></u>
