The common difference of the given sequence is x + y
From the question, we are to determine the common difference of the given sequence
The given sequence is
3x + 2y, 4x + 3y, 5x + 4y,
That is,
a1 = 3x + 2y
a2 = 4x + 3y
a3 = 5x + 4y
Common difference = a2 - a1 = a3 - a2
Thus,
Common difference = 4x + 3y - (3x + 2y)
Common difference = 4x + 3y - 3x - 2y
Common difference = 4x - 3x + 3y - 2y
Common difference = x + y
Hence, the common difference is x + y
Learn more on Calculating common difference here: brainly.com/question/8261794
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