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qaws [65]
3 years ago
14

Help like I do not understand math at all

Mathematics
2 answers:
Fynjy0 [20]3 years ago
7 0
Parts A:There will be 57 rows
Part B: because 513 divided by 9 equals 57
Part C:equals 25 because if you divide 250 by 5 and then divide it by 2 u get 25
yKpoI14uk [10]3 years ago
5 0

Answer:

Step-by-step explanation:

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PLEASE SHOW WORK OR EXPLAIN
timofeeve [1]

Answer:

<h3>20.6 ft</h3>

Step-by-step explanation:

You must use the trigonometric function.

In this case, it will be tangent.

tangent=\dfrac{opposite}{adjacent}

We have

\theta=38^o,\ opposite=r,\ adjacent=20

\tan38^\approx0.7813

Substitute:

\tan38^o=\dfrac{r}{20}

\dfrac{r}{20}=0.7813              <em>multiply both sides by 20</em>

r=15.626

Tree height is r + 5.

Therefore

r+5=15.626+5=20.626\approx20.6\ ft

7 0
3 years ago
How can you you tell when a pattern shows counting on by tens
astraxan [27]
You can ise repeated reasonings
6 0
3 years ago
What assumption have you made in answering part b​
emmasim [6.3K]

You're assuming that this data set represents all of Mrs. Hassaan's pupils. Certain students could be missing from the histogram - for instance, there could be one or two students who missed the test, but for certain reasons will be taking a make-up exam. Their grade would not be recording in this data set, but they still contribute to the class size, and so would be unaccounted for here.

4 0
3 years ago
Given the following right triangle, find cose, sine, tane sececsce, and cote. Do not
IgorLugansk [536]

Step-by-step explanation:

Use the Pythagorean theorem:

leg^2+leg^2=hypotenuse^2

We have

leg=4,\ hypotenuse=10

Substitute:

4^2+leg^2=10^2

16+leg^2=100             <em>subtract 16 from both sides</em>

leg^2=84\to leg=\sqrt{84}\\\\leg=\sqrt{(4)(21)}\\\\leg=\sqrt4\cdot\sqrt{21}\\\\leg=2\sqrt{21}

sine=\dfrac{opposite}{hypotenuse}\\\\cosine=\dfrac{adjacent}{hypotenuse}\\\\tangent=\dfrac{opposite}{adjacent}\\\\cotangent=\dfrac{adjacent}{opposite}\\\\secant=\dfrac{hypotenuse}{adjacent}\\\\cosecant=\dfrac{hypotenuse}{opposite}

Substitute:

hypotenuse=10,\ opposite=4,\ adjacent=2\sqrt{21}

\sin\theta=\dfrac{4}{10}=\dfrac{2}{5}\\\\\cos\theta=\dfrac{2\sqrt{21}}{10}=\dfrac{\sqrt{21}}{5}\\\\\tan\theta=\dfrac{4}{2\sqrt{21}}=\dfrac{2}{\sqrt{21}}\cdot\dfrac{\sqrt{21}}{\sqrt{21}}=\dfrac{2\sqrt{21}}{21}\\\\\cot\theta=\dfrac{2\sqrt{21}}{4}=\dfrac{\sqrt{21}}{2}\\\\\sec\theta=\dfrac{10}{2\sqrt{21}}=\dfrac{5}{\sqrt{21}}\cdot\dfrac{\sqrt{21}}{\sqrt{21}}=\dfrac{5\sqrt{21}}{21}\\\\\csc\theta=\dfrac{10}{4}=\dfrac{5}{2}

5 0
4 years ago
What is the density of 72g over 24cm?
diamong [38]
Mass/volume 72g/24 cubic cm Is equal to 3G per cubic centimeter
5 0
3 years ago
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