Yes.
For example, the LCM of 12 and 36 is 36, because factoring these numbers gives
12 = 2^2 * 3
36 = 2^2 * 3^2
So, to match them, just multiply the twelve by 3, then they're both 36.
Answer:
A. (-7 -2)
Step-by-step explanation:
You can eliminate y by multiplying the first equation by 7 and subtracting 6 times the second equation:
7(-3x +6y) -6(5x +7y) = 7(9) -6(-49)
-21x +42y -30x -42y = 63 +294 . . . . eliminate parentheses
-51x = 357 . . . . . . . . collect terms
x = -7 . . . . . . . divide by -51. This matches answer choice A.
Answer:
The probability that she gets all the red ones, given that she gets the fluorescent pink one, is P=0.0035 or 0.35%.
Step-by-step explanation:
Susan grabs four marbles at random.
We have to calculate the probabilities that he picks the 3 red ones, given that she already picked the fluorescent pink.
If it is given that the fluorescent pink is already picked, we are left with three red marbles, four green ones, two yellow ones, and four orange ones. A total of 13 marbles.
The probability that the second marble is red is 3 in 13.
The probability that the third marble is also red is 2 (the red marbles that are left) in 12 (the total amount of marbles left), as there is a picking without replacement.
The probability that the fourth marble is 1 in 11.
Then, the probability that the 3 red marbles are picked, is:

The sum of the 2 angles will add up to 180°
Answer: A 24 cm piece of string is cut into two pieces , one piece is used to form a circle and the other piece is used to form a square.
How should this string be cut so that the sum of the areas is a minimum .
:
Let x = the circumference of the circle
then
(24-x) = the perimeter of the square
:
Find the area of the circle
find r
2*pi*r = x
r =
Find the area of the circle
A =
A =
A = sq/cm, the area of the circle
:
Find the area of the square
A = sq/cm the area of the square
The total area
At = +
Graph this equation, find the min
Min occurs when x=10.6 cm
cut string 10.6 cm from one end
Step-by-step explanation: Hope I help out alot (-: :-)