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3 years ago

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Determine both domain and range

1 answer:

irina1246 [14]3 years ago

8 0

Answer:

Another way to identify the domain and range of functions is by using graphs. Because the domain refers to the set of possible input values, the domain of a graph consists of all the input values shown on the x-axis. The range is the set of possible output values, which are shown on the y-axis

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Which of the following expressions are equivalent to 4+(14-2)4+(14−2)4, plus, left parenthesis, 14, minus, 2, right parenthesis?

ch4aika [34]

Answer:The Answer is C,D and E

Step-by-step explanation:I just answered it on khan academy

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3 years ago

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Write the following equation in slope-intercept form.<br> 3x - 2y=5

prisoha [69]

Answer:

y = 3/2x -5/2

Step-by-step explanation:

Slope intercept form is

y = mx+b where m is the slope and b is the y intercept

3x- 2y = 5

Solve for y

Subtract 3x from each side

3x -3x- 2y =-3x+ 5

-2y = -3x+5

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3 years ago

7(2x+6)=1 plzzz Yelp

Ierofanga [76]

Answer:

$x=-\dfrac{41}{14}$

Step-by-step explanation:

$7(2x+6)=1$

Expand parentheses:

$14x+42=1$

Subtract 42 from both sides:

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$x=-\dfrac{41}{14}$

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2 years ago

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What is the value of x?

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Jason and Jill or two students in mr. White's math class. On the last 5 quizzes Jason scored an 80 90 95 85 and 70. Jill scored

Mrac [35]

Jason's scores : 80 90 95 85 70 and

Jill's score : 70 75 90 100 95.

Mean of Jason's scores = $\frac{80 + 90 + 95 + 85 + 70}{5}=\frac{420}{5}=84.$

Mean of Jill's scores = $\frac{70+75+90+100+95}{5}=\frac{430}{5}=86$

Now, in order to find the mean absolute deviation, need to find the difference of each score from means.

<u>Mean absolute deviation for Jason's scores.</u>

|84-80| = 4

|84-90| = 6

|84-95| = 9

|84-85| = 1

|84-70|= 14

$\frac{4+6+9+1+14}{5}=\frac{34}{5}=6.8$

<u>Mean absolute deviation for Jill's scores</u>

|86-70| = 16

|86-75| = 11

|86-90| = 4

|86-100| = 14

|86-95|= 9

$\frac{16+11+4+14+9}{5}=\frac{54}{5}=10.8$

Jill got average quiz score 86 and Jason got 84.

Therefore, Jill got better quiz average.

Also, the mean absolute deviation for Jason scores is less that is 6.8 than 10.8.

Therefore, Jason got more consistent grades.

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3 years ago