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Pavel [41]
1 year ago
6

Solve the following system of linear equations using elimination. 3r- y=5 x=y=1

Mathematics
1 answer:
Natali [406]1 year ago
7 0

3x - y = 5 Equation l

x - y = 1 Equation ll

By elimination

-Multiply equation l by -1

-3x + y = -5

x - y = 1

-2x = -4

Solve for x

x = -4/-2

x = 2

-Find y

2 - y = 1

-y = 1 - 2

-y = -1

y = -1/-1

y = 1

Solurtion: x = 2, y = 1

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vlabodo [156]

Of the 12 available months, r=4 of them end in the letter "r" (Sep, Oct, Nov, Dec). The sample space consists of all 12 possible choices of 1 month, but the only outcome we care about is any 1 of these 4 being selected. The probability of choosing any one of these is \dfrac4{12}=\dfrac13\approx0.33. How you describe the probability is up to interpretation, but probably a good convention to use is to say that an event is "unlikely" to happen if that event has a probability less than 0.5 of occurring.

8 0
3 years ago
Among 20 olden hamster litters recorded, there was a sample mean of baby hamsters, with a sample standard deviation of. Create a
Virty [35]

Answer:

7.72-2.433\frac{2.5}{\sqrt{20}}=6.360    

7.72+2.433\frac{2.5}{\sqrt{20}}=9.080    

So on this case the 97.5% confidence interval would be given by (6.360;9.080)    

Step-by-step explanation:

For this case we assume the deviation given as s =2.5 and the mean \bar = 7.72

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=7.72 represent the sample mean

\mu population mean (variable of interest)

s=2.5 represent the sample standard deviation

n=20 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=20-1=19

Since the Confidence is 0.975 or 97.5%, the value of \alpha=0.025 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.0125,19)".And we see that t_{\alpha/2}=2.433

Now we have everything in order to replace into formula (1):

7.72-2.433\frac{2.5}{\sqrt{20}}=6.360    

7.72+2.433\frac{2.5}{\sqrt{20}}=9.080    

So on this case the 97.5% confidence interval would be given by (6.360;9.080)    

3 0
3 years ago
Which polynomial is prime?
Anastaziya [24]

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6 0
3 years ago
Read 2 more answers
Please Simplify the expression √169.
Vanyuwa [196]
√169 

Answer is =13

13*13
= 169

Hope it helped you, and have a great day.

-Charlie 

Thank you so much!!!!!!!
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