Answer:
4: 1/16; 6: 1/8; 8: 3/16; 10: 1/4; 12: 3/16; 14: 1/8; 16: 1/16
Step-by-step explanation:
The table attached shows the sum resulting from the roll of two 4-sided dice marked as you say. There are 16 possible outcomes, assumed to be equally likely.
There is 1 way to roll a sum of 4, so its probability is 1/16.
There are 2 ways to roll a sum of 6, so its probability is 2/16 = 1/8.
There are 3 ways to roll a sum of 8, so its probability is 3/16.
There are 4 ways to roll a sum of 10, so its probability is 4/16 = 1/4.
There are 3 ways to roll a sum of 12, so its probability is 3/16.
There are 2 ways to roll a sum of 14, so its probability is 2/16 = 1/8.
There is 1 way to roll a sum of 16, so its probability is 1/16.
We will have the following:
*First: We determine the translation rule:
We have that the point went from (3, -4) to (0, -5), thus the translation rule would be:
Second: We apply the translation rule to the other point to determine it's image, that is:
So, the image of the second point is (5, 6).
, and
. Subtracting this from the numerator gives a remainder of
, and
. Subtracting this from the previous remainder gives a new remainder of
is not a multiple of
, so we're done. Then