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goldenfox [79]
1 year ago
12

Solving Linear Inequalities HELP PLEASE(┬┬﹏┬┬)

Mathematics
1 answer:
Snezhnost [94]1 year ago
6 0

In Step 2 have a mistake in student solution so the option B is correct answer.

In the given question,

A student solved the inequality \frac{-x+4}{3} > \frac{x+1}{2}.

We have to find the error in the student solution.

To find the mistake we first solve the give inequality.

The equality is \frac{-x+4}{3} > \frac{x+1}{2}

To solve this equality we firstly equal the denominator by multiplying and divide 2 on left side and 3 on right side.

So \frac{2}{2}\times\frac{-x+4}{3} > \frac{x+1}{2}\times\frac{3}{3}

Now simplifying

\frac{2(-x+4)}{6} > \frac{3(x+1)}{6}

Now simplifying the brackets of numerator ob both side using distributive property.

In Distributive Property: a(b+c)=ab+bc

\frac{2\times(-x)+2\times4}{6} > \frac{3\times x+3\times1}{6}

\frac{-2x+8}{6} > \frac{3x+3}{6}

Since the both side have same numerator. So we can write the inequality as

-2x+8 > 3x+3

Subtract 8 on both side

-2x+8-8 > 3x+3-8

-2x > 3x-5

Subtract 3x on both side

-2x-3x > 3x-5-3x

-5x > -5

Divide by -5 on both side

-5/-5 x > -5/-5

x > 1

Hence the value of x is greater than 1.

Now we see the step on student.

We can see that in step 2 has mistake. In step 2 student doesn't use distributive property to solve the bracket.

Hence, we can say that option 2 is correct.

To learn more about Distributive Property link is here

brainly.com/question/5637942

#SPJ1

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