The coordinates of the vertices of the image are L' = (-4, 6), M' = (-5, 1) and N' = (-7, 3)
<h3>What are the coordinates of the vertices of the image?</h3>
The vertices of the preimage of the triangle are given as:
L = (4, -6)
M = (5, -1)
N = (7, -3)
The rotation is given as: 180 degrees counterclockwise
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The rule of this rotation is
(x, y) => (-x, -y)
So, we have:
L' = (-4, 6)
M' = (-5, 1)
N' = (-7, 3)
Hence, the coordinates of the vertices of the image are L' = (-4, 6), M' = (-5, 1) and N' = (-7, 3)
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Answer:
x = -10
Step-by-step explanation:
first you multiply both sides by -3
x + 7 = -3
then you subtract 7 from both sides
x = -10
hope this helps
Answer:
h = 84
Step-by-step explanation:
3 = 87 - h
h + 3 = 87 (Add h to both sides)
h = 84 (Subtract 3 from both sides)
Answer:
it depends
Step-by-step explanation:
If 17 is the hypotenuse

if you are looking for the hypotenuse
