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Tcecarenko [31]

1 year ago

14

A car dealership pays $8,350 for a car. They Mark up the price by 17.4% to get the retail price. What is the retail price of the

car at this dealership? Round the answer to tge nearest (hundredth) secon decimal place.

1 answer:

olga55 [171]1 year ago

6 0

A car dealership pays the sum of $8,350 for a car

The dealer mark up the car price by 17.4%

The retail price = Mark up percentage x original price of the car

Mark up = 17.4%

= 17.4 + 10

= 117.4%

Convert 117.4% to decimal

= 117.4/100

= 1.174

The retail price = $8, 350 x 1.174

= $9,802.90

The retail price of the car is $9,802.90

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700=132.69x-25.96 <br> solve please

Damm [24]

Answer:

x = 5.5 (rounded)

Step-by-step explanation:

Equation: 700 = 132.69x - 25.96

Add 25.96 to both sides: 700+25.96 = 132.69x -25.96 + 25.96

Simplify: 725.96 = 132.69x

Isolate x

Divided both sides by 132.69: $\frac{725.96}{132.69} = \frac{132.69x}{132.69}$

Simplify: x = 5.5 (rounded)

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3 years ago

Junior's brother is 1 1/2

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Answer:

Step-by-step explanation:

1 1/5 of 1 1/2 meters

= (1+1/5) x (1+1/2)

= 1x1 + 1x1/2 + 1x1/5 + 1/5*1/2

= 1 + 1/2 + 1/5 + 1/10

= 1 + (1x5+1x2+1)/10

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3 years ago

A rectangular box with a volume of 272ft^3 is to be constructed with a square base and top. The cost per square foot for the bot

ASHA 777 [7]

Answer:

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

The length of one side of the base of the given box is 3 ft.

The height of the box is 30.22 ft.

Step-by-step explanation:

Given that, a rectangular box with volume of 272 cubic ft.

Assume height of the box be h and the length of one side of the square base of the box is x.

Area of the base is = $(x\times x)$

$=x^2$

The volume of the box is = area of the base × height

$=x^2h$

Therefore,

$x^2h=272$

$\Rightarrow h=\frac{272}{x^2}$

The cost per square foot for bottom is 20 cent.

The cost to construct of the bottom of the box is

=area of the bottom ×20

$=20x^2$ cents

The cost per square foot for top is 10 cent.

The cost to construct of the top of the box is

=area of the top ×10

$=10x^2$ cents

The cost per square foot for side is 1.5 cent.

The cost to construct of the sides of the box is

=area of the side ×1.5

$=4xh\times 1.5$ cents

$=6xh$ cents

Total cost = $(20x^2+10x^2+6xh)$

$=30x^2+6xh$

Let

C $=30x^2+6xh$

Putting the value of h

$C=30x^2+6x\times \frac{272}{x^2}$

$\Rightarrow C=30x^2+\frac{1632}{x}$

Differentiating with respect to x

$C'=60x-\frac{1632}{x^2}$

Again differentiating with respect to x

$C''=60+\frac{3264}{x^3}$

Now set C'=0

$60x-\frac{1632}{x^2}=0$

$\Rightarrow 60x=\frac{1632}{x^2}$

$\Rightarrow x^3=\frac{1632}{60}$

$\Rightarrow x\approx 3$

Now $C''|_{x=3}=60+\frac{3264}{3^3}>0$

Since at x=3 , C''>0. So at x=3, C has a minimum value.

The length of one side of the base of the box is 3 ft.

The height of the box is $=\frac{272}{3^2}$

=30.22 ft.

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

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We end up with 7xy(4x-7y^4)

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