A bike race takes place over a 3 mile course.How many feet is it

2 answers:

8 0

There are 5,280 feet in 1 mile.

The 1st mile of the race is 5,280 ft.
The 2nd mile of the race is 5,280 ft.
The 3rd mile of the race is 5,280 ft.
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The total distance is 15,840 ft.

With a calculator, you enter 3 x 5280 =

marissa [1.9K]4 years ago

3 0

5280 feet = 1 mile
So, multiply 5280 and 3 to get your answer.
You should get: 15840 feet

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A steady wind blows a kite due west. the kite's height above ground from horizontal position x = 0 to x = 120 ft is given by y =

professor190 [17]

The derivative of the vertical position is
.. y' = 2/40*(x -50)
so the integral that gives the length of the curve the kite traveled is
$distance= \int\limits^{120}_{0} {\sqrt{1+(\frac{1}{20}(x-50))^{2}} \, dx$

It is convenient to let a graphing calculator compute this integral numerically. If you want to do it analytically, a table of integrals can be handy. The indefinite integral is
$\frac{x-50}{40} \sqrt{(x-50)^{2}+400} +10 arcsinh(\frac{x-50}{20})$
This evaluates to
$\frac{1}{2}(25 \sqrt{29} +35 \sqrt{53}) +10(arcsinh( \frac{5}{2}) +arcsinh( \frac{7}{2})) \approx 230.8$ feet