Answer:
yes
Step-by-step explanation:
Let's make a table to see the total price for different numbers of tickets.
Number of tickets 111 222 333
Total price \$10.50$10.50dollar sign, 10, point, 50 \$21$21dollar sign, 21 \$31.50$31.50dollar sign, 31, point, 50
Hint #22 / 4
For each number of tickets bought, let's write the relationship of total price to number of tickets as a ratio in simplest form.
\dfrac{\$10.50}{1} = \$10.50 ~~~~~~~~~\dfrac{\$21}{2} = \$10.50 ~~~~~~~~~\dfrac{\$31.50}{3} = \$10.50
1
$10.50
=$10.50
2
$21
=$10.50
3
$31.50
=$10.50start fraction, dollar sign, 10, point, 50, divided by, 1, end fraction, equals, dollar sign, 10, point, 50, space, space, space, space, space, space, space, space, space, start fraction, dollar sign, 21, divided by, 2, end fraction, equals, dollar sign, 10, point, 50, space, space, space, space, space, space, space, space, space, start fraction, dollar sign, 31, point, 50, divided by, 3, end fraction, equals, dollar sign, 10, point, 50
Hint #33 / 4
All of the ratios between the two quantities can be simplified to \$10.50$10.50dollar sign, 10, point, 50, so the quantities are proportional.
Hint #44 / 4
The answer: Yes
