A box-and-whisker plot shows 5 number summary: Class A Class B1) minimum value 65 562) 1st quartile 66 793) median 81 914) 3rd quartile 89 945) maximum value 95 100
Interquartile range = 3rd Quartile - 1st Quartile Class A: 89 - 66 = 23Class B: 94 - 79 = 15
IQR indicates the spread of the of the scores over the median. Class A has a spread that his more than 50% of the scores of Class B.
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Answer:
A = 70 mm²
Step-by-step explanation:
The area (A) of a trapezoid is calculated as
A = 
h (b₁ + b₂)
where h is the perpendicular height and b₁, b₂ the parallel bases
Here h = 10, b₁ = 10, b₂ = 4 , then
A = × 10 × (10 + 4) = 5 × 14 = 70 mm²
Cos 157.5º=-cos (180º-157.5º)=-cos 22.5=-cos(45/2)
cos Ф/2=⁺₋√((1+cosФ)/2).
In this case 157.5º is in the second quadrant, therefore we use the following equation:
cos Ф/2=-√((1+cosФ)/2). (we will have a negative number)
cos 157.5º=-cos (45/2)=-√((1+cos 45º)/2)
=-√((1+√2/2)/2)
=-√((2+√2)/4)
=-√(2+√2) / 2 (≈-0.92387...)
Answer: cos 157.5º= -√(2+√2) / 2
Answer:
6.45
Step-by-step explanation:
The answer=2.5*7.5-(2.75+9.55)=18.75-(12.3)=6.45
A half a dollar is 50 cents. If you want to use quarters, you would need 6 more quarters to make 2 dollars.
