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Archy [21]
3 years ago
7

Write an equation in slope-intercept form using the given information about each line.

Mathematics
1 answer:
mel-nik [20]3 years ago
6 0

9514 1404 393

Answer:

  y = 1/2x +7

Step-by-step explanation:

I like to start with the 2-point equation for a line.

  y = (y2 -y1)/(x2 -x1)(x -x1) + y1

  y = (9 -8)/(4 -2)(x -2) +8 . . . . . fill in point values

  y = 1/2(x -2) +8 . . . . . simplify a bit

  y = 1/2x +7

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A bicycle wheel with diameter 16 inches rides over a screw in the street. The screw is on level ground before it
34kurt

Answer:

16 inches

Step-by-step explanation:

<em>Note: it should say 56π inches instead of 56 inches otherwise no option is correct</em>

<u>Given</u>

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andreev551 [17]

The roots of an equation are simply the x-intercepts of the equation.

See below for the proof that \mathbf{\frac{x^4}{2021} = 2021x^2 - x - 3 = 0} has at least two real roots

The equation is given as: \mathbf{\frac{x^4}{2021} = 2021x^2 - x - 3 = 0}

There are several ways to show that an equation has real roots, one of these ways is by using graphs.

See attachment for the graph of \mathbf{\frac{x^4}{2021} = 2021x^2 - x - 3 = 0}

Next, we count the x-intercepts of the graph (i.e. the points where the equation crosses the x-axis)

From the attached graph, we can see that \mathbf{\frac{x^4}{2021} = 2021x^2 - x - 3 = 0} crosses the x-axis at approximately <em>-2000 and 2000 </em>between the domain -2500 and 2500

This means that \mathbf{\frac{x^4}{2021} = 2021x^2 - x - 3 = 0} has at least two real roots

Read more about roots of an equation at:

brainly.com/question/12912962

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