a jogger begins her workout by jogging to a park, a distance of 12 miles. she then jogs home at the same speed, but along a diff

Question

1 year ago

7

erent route. this return trip is 18 miles, and her time is one hour longer. find her jogging speed.

1 answer:

sukhopar [10] · Answer 1 · 2024-07-06T14:22:20+03:00

The jogging speed of the jogger is 6 miles/hour.

Given that:-

Distance from home to park = 12 miles

Distance from park tp home from a different route = 18 miles

It is also given that the time taken to reach home from park is 1 hour longer than the number of hours taken to reach park from home.

We have to find the speed of the jogger.

Let the time taken by jogger to reach park from home be t hours.

Hence, according to the data given in the question,

Time taken by jogger to reach home from park is (t+2) hours.

We know that,

Speed = distance/time

We know that the speed of jogger in each route is same.

Hence, we can write,

12/t = 18/(t+1)

2/t = 3/(t+1)

2(t+1) = 3t

2t+2 = 3t

t = 2 hours.

Hence, speed of the jogger = 12/2 = 6 = 18/(2+1) = 18/3.

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