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vesna_86 [32]
3 years ago
5

If the original rectangle has an area of 2 cm squared and the scaled copied has an area of 50 cm squared what is the scale facto

r used to draw the scaled copy
Mathematics
1 answer:
vazorg [7]3 years ago
8 0

Answer:

The scale factor used to draw the scaled copy is a factor of 5

Step-by-step explanation:

Here, we are interested in calculating the scale factor which was used to transition the original rectangle to the new scaled copy.

Firstly, there is a way to relate how the scale factor of the sides relate to the scale factor of the area. What we are saying here is that the scale factor of the sides is never equal to that of the area;

For a 2 cm^2 area let’s say the sides are 1 by 2 ; this gives us an area as said

Now, to get 50cm^2, we can see that the scale factor of both areas is 25 (2 to 50)

So the area has been scaled 25 times the original area. So how has the sides been scaled?

Using a general principle, the scale used to scale the area is the square of the scale used to scale the sides. What are we saying here? if the area is scaled by 4, then the sides are scaled by 2

So in this particular case, the area is scaled by a factor of 25

Now, the scale factor of the sides will be the positive square root of this which is 5

Hence, we can conclude that the sides of the smaller triangles were each multiplied by 5 to arrive at the sides of the bigger one which makes it that the scale factor used to draw the scaled copy is 5

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For the line segment whose endpoints are X(1, 2) and Y(6, 7), find the x value for the
finlep [7]

Answer:

3) 2.7

Step-by-step explanation:

The distance between two points (x_1,y_1) and (x_2,y_2) can be determined by:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Since the points are X(1, 2) and Y(6, 7). The distance between the two points is

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}=\sqrt{(6-1)^2+(7-2)^2}=\sqrt{50}

the x value for the  point located 1/3 the distance from X to Y,

x=\frac{x_2-x_1}{3}=\frac{6-1}{3}=1.7

The x value = x_1+1.7 = 1+1.7 = 2.7

6 0
3 years ago
Read 2 more answers
A student carried out an experiment to determine the amount of vitamin C in a tablet sample. He performed 5 trials to produce th
ivolga24 [154]

Answer:

There is not enough evidence to support the claim that the amount of vitamin C in a tablet sample is different from 500 mg.

P-value = 0.166.

Step-by-step explanation:

We start by calculating the mean and standard deviation of the sample:

M=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M=\dfrac{1}{5}(490+502+505+495+492)\\\\\\M=\dfrac{2484}{5}\\\\\\M=496.8\\\\\\s=\sqrt{\dfrac{1}{n-1}\sum_{i=1}^n\,(x_i-M)^2}\\\\\\s=\sqrt{\dfrac{1}{4}((490-496.8)^2+(502-496.8)^2+(505-496.8)^2+(495-496.8)^2+(492-496.8)^2)}\\\\\\s=\sqrt{\dfrac{166.8}{4}}\\\\\\s=\sqrt{41.7}=6.5\\\\\\

Then, we can perform the hypothesis t-test for the mean.

The claim is that the amount of vitamin C in a tablet sample is different from 500 mg.

Then, the null and alternative hypothesis are:

H_0: \mu=500\\\\H_a:\mu< 500

The significance level is 0.05.

The sample has a size n=5.

The sample mean is M=496.8.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=6.5.

The estimated standard error of the mean is computed using the formula:

s_M=\dfrac{s}{\sqrt{n}}=\dfrac{6.5}{\sqrt{5}}=2.907

Then, we can calculate the t-statistic as:

t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{496.8-500}{2.907}=\dfrac{-3.2}{2.907}=-1.1

The degrees of freedom for this sample size are:

df=n-1=5-1=4

This test is a left-tailed test, with 4 degrees of freedom and t=-1.1, so the P-value for this test is calculated as (using a t-table):

\text{P-value}=P(t

As the P-value (0.166) is bigger than the significance level (0.05), the effect is not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the amount of vitamin C in a tablet sample is different from 500 mg.

4 0
3 years ago
PLEASE HURRY I’M TIMED
bekas [8.4K]
The correct answer would be A 355.5

If you take the base number of 35.55 and multiply is by 100 it should be 3,555 cm not 355.5 cm
7 0
3 years ago
Read 2 more answers
Find 3x2 − y3 − y3 − z if x = 3, y = −2, and z = −5.
IceJOKER [234]
3x²-y³ - y³ - z        if x = 3, y = -2, z = -5

Simply plug in all the values :)

3(3²) - (-2³) - (-2³) - (-5)

Simplify.

3(9) + 2³ + 2³ + 5

Simplify.

27 + 8 + 8 + 5

Simplify.

35 + 13

Simplify.

48

~Hope I helped!~
4 0
3 years ago
Branden and Pete both play running back. Branden carries the ball 75 times for 550 yards and Pete had 42 carries for 380 yards w
mars1129 [50]

Answer:

Pete runs farther per carry.

Step-by-step explanation:

Given:

Branden and Pete both play running back.

Branden carries the ball 75 times for 550 yards.

Pete had 42 carries for 380 yards

Question asked:

Who runs farther per carry ?

Solution:

First of all we find each boy's distance covered per carry:-

<u>For Branden</u>

Branden carries the ball 75 times for = 550 yards.

Branden carries the ball 1 time for = \frac{550}{75} =7.34\ yard

<u>For Pete </u>

Pete carries 42 times for = 380 yards

Pete carries 1 time for = \frac{380}{42} =9.05\ yards

As Pete runs 9.05 yards for 1 carry while Branden runs 7.34 yards for 1 carry, hence Pete runs farther per carry.

3 0
3 years ago
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