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Zina [86]
2 years ago
11

2(vh)/k=r Solve equation for v in terms of all other variables involved

Mathematics
1 answer:
aivan3 [116]2 years ago
6 0

The equation v in terms of other variables is v = kr/2h

<h3>What is the subject of an equation?</h3>

It is a variable which is expressed in terms of other variables involved in the formula.

Formulas are written so that a single variable, the subject of the formula is on the L.H.S. of the equation. Everything else goes on the right side of the equation. We evaluate the formula by substituting for the literal numbers on the right hand side.

2(vh) / k = r

by cross multiplication

2(vh) = kr

divide both sides by 2h

v = kr/2h

In conclusion, v in terms of other variables is  kr/2h

Learn more about subject of an equation: brainly.com/question/657646

#SPJ1

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Natasha, Peter and Malachy share £56 in a ratio 1:1:2. How much money does each person get?
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Answer:

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Step-by-step explanation:

Add 1+1+2=4

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Y = x + 2<br> y = 3x - 4
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y=x+2

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Read 2 more answers
A news item is spreading by word of mouth through a population of size 12,000 people. After t days, the number of people (in tho
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Answer:

a) 2.303

b) f'(t)=\frac{432e^{-0.48t}}{(1+75e^{-0.48t})^{2}}

c) 1.3609

e) \frac{dy}{dx}=0.04y(12-y)

f)  4.5 thousand people(smaller)

7.5 thousand people (larger)

e) t=7.93 days (smaller)

t=10.06 days (larger)

g) 1.44

Step-by-step explanation:

The given function is y=f(t)=\frac{12}{1+75e^{-0.48t}}

To find how many thousand people have heard the news after 6 days, we substitute to get:

f(6)=\frac{12}{1+75e^{-0.48*6}}=2.303  thousands.

b) We rewrite to get: f(t)=12(1+75e^{-0.48t})^{-1}

We differentiate using the chain rule to obtain:

f'(t)=-12(1+75e^{-0.48t})^{-2}\cdot 75e^{-0.48t}\cdot -0.48

This simplifies to:

f'(t)=432e^{-0.48t}(1+75e^{-0.48t})^{-2}

We rewrite as positive index to get:

f'(t)=\frac{432e^{-0.48t}}{(1+75e^{-0.48t})^{2}}

c) To find the rate at which the news is spreading after 8 days, we substitute t=8 into f'(t)=\frac{432e^{-0.48t}}{(1+75e^{-0.48t})^{2}} to get:

f'(8)=\frac{432e^{-0.48\cdot 8}}{(1+75e^{-0.48\cdot 8})^{2}}=1.3609

d) The solution to the logistic differential equation:

\frac{dy}{dt}=ky(M-y)

is

y=\frac{M}{1+be^{-Mkt}}

By comparison, M=12, and Mk=0.48

12k=0.48\\k=0.04

The differential equation is:

\frac{dy}{dx}=0.04y(12-y)

e) To how many people have heard the news when its rate of spread is 1.35 thousand per day, we equate the differential equation to 1.35 and so for t first.

\frac{432e^{-0.48t}}{(1+75e^{-0.48t})^{2}}=1.35

This gives us: t=10.06 ot t=7.93

We substitute the times into the function to get:

f(7.93)=\frac{12}{1+75e^{-0.48\cdot7.93}}=4.5 thousand: smaller value

f(10.06)=\frac{12}{1+75e^{-0.48\cdot10.06}}=7.5 thousand: Larger value

f) The two times that the news is spreading at rate 1.35 thousand people per day are:

t=7.93 days: Smaller value

t=10.06: Larger value

g) To find the fastest rate at which the news spread we take the second derivative and equate it to zero.

f''(t)=0

This corresponds to where the horizontal line is tangent to

f'(t)=\frac{432e^{-0.48t}}{(1+75e^{-0.48t})^{2}}

From the graph the point of tangency is:

(8.99,1.44)

Therefore the fastest rate at which the news spread is 1.44

7 0
3 years ago
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