The normal distribution curve for the problem is shown below
We need to standardise the value X=405.5 by using the formula


We now need to find the probability of z=0.32 by reading the z-table
Note that z-table would give the reading to the left of z-score, so if your aim is to work out the area to the right of a z-score, then you'd need to do:

from the z-table, the reading

gives 0.6255
hence,

The probability that the mean weight for a sample of 40 trout exceeds 405.5 gram is 0.3475 = 34.75%
to get the inverse of any expression, we start off by doing a quick switcheroo on the variables and then solve for "y".

Answer: D=3(h-2)
Explanation —>
Answer:
1:3
Step-by-step explanation:
There are 3 adults per 1 child at the book fair. I think this is right but im not 100% sure :)