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Serga [27]
3 years ago
14

What is the largest three-digit number divisible by 24 and 54?

Mathematics
1 answer:
tensa zangetsu [6.8K]3 years ago
4 0

Answer:

The largest three-digit number divisible by 24 and 54 is:

  • <u>864</u>

Step-by-step explanation:

To identify the largest number what I did was dividing 999 (the largest whole three-digit number of all) in the first number given (24):

  • \frac{999}{24}=41.625

With this number, you know that you must multiply 24 by a number like 41 or less until you find a number that can be divisible by 54 and obtain a whole number, so:

  • 24*41= 984/54= 18.22 (how the number obtained is not a whole number, this is not the correct).
  • 24*40= 960/54= 17.77 (this is not).
  • 24*39= 936/54= 17.33 (this is not).
  • 24*38= 912/54= 16.88 (this is not).
  • 24*37=888/54= 16.44 (this is not).
  • <u>24*36= 864/54= 16 (This is the correct</u>).

Now, you have identified that the number 864, you can prove it by dividing this in 24 and 54:

  • \frac{864}{24}=36
  • \frac{864}{54}= 16

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If the perimeter of the rectangle is 60 in, find its area.

If the perimeter of the rectangle is 60 in, find its area.

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Hoped it help! :D
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Solve completely (all missing sides and all missing angles) using trig ratios or laws. Round to the nearest tenth.
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Answer:

Step-by-step explanation:

3. Use Cosine law to find the  length of the unknown side (PR)

q² = p² +  r² - 2prCos Q

q is the opposite side of ∠Q;  

p is the opposite side of ∠P; p = 33

r is the opposite sides of ∠R ; r = 67

q² = 33² + 67² -  2* 33*67 Cos 19°

    = 1089 + 4489 - 4422 * 0.95

     = 1089 + 4489 - 4200.9

    = 1377.1

q = √1377.1

q = 37.1

PR = 37.1

To find the angle use law of sin

\sf \dfrac{q}{Sin \ Q} =\dfrac{p}{Sin \ P}\\\\\\\dfrac{37.1}{Sin \ 19}=\dfrac{33}{Sin \ P} \\\\\\\dfrac{37.1}{0.33}=\dfrac{33}{Sin \ P}\\\\\\37.1* Sin \ P = 33 *0.33\\\\Sin \ P =\dfrac{33*0.33}{37.1}

Sin P = 0.3

P = Sin^{-1} 0.3\\

P = 17.5°

∠R = 180 - (19 + 17.5)

    = 143.5°

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