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Vinvika [58]
1 year ago
14

Not a timed or graded assignment. Please decompose the number inside of radical using primes. Quick answer = amazing review :)

Mathematics
1 answer:
ss7ja [257]1 year ago
7 0

SOLUTION

The given expression is:

-5\sqrt[]{147\times r^{13}\times s^8}

Rewrite the expression

-5\sqrt[]{49\times3\times r^{12}\times r^1\times s^{4\times2}}

This further give

\begin{gathered} -5\sqrt[]{49\times3\times(r^6)^2\times r^1\times(s^4)^2} \\ =-5\times7\times r^6\times s^4\sqrt[]{3\times r} \\ =-35r^6s^4\sqrt[]{3r} \end{gathered}

Therefore, the solution is

-35r^6s^4\sqrt[]{3r}

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Answer:

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6 0
3 years ago
Factorize 2x^4-7x^3-13x^2+63x-45 using factor theorem.
zheka24 [161]
Find the possible rational roots and use synthetic division to find the first zero.
I chose x=1 (which represents the factor "x-1")

1║2  -7  -13    63  -45
  ║     2    -5  -18    45
    2  -5  -18    45    0
(x-1) is a factor, (2x³ - 5x² - 18x + 45) is the other factor.

Use synthetic division on the decomposed polynomial to find the next zero.
I chose x = 3 (which represents the factor "x-3")

3║2  -5  -18    45 
  ║     6     3   -45   
    2   1  -15     0   

Using synthetic division, we discovered that (x-1), (x-3), & (2x² + x -15) are factors.  Take the new decomposed polynomial (2x² + x -15) and find the last two factors using any method.

Final Answer: (x-1)(x-3)(x+3)(2x-5)




8 0
3 years ago
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