Answer:
It is the graph of f(x) shifted 2 units right and 4 units up.
A is correct.
Step-by-step explanation:
We are given two function. One is parent function and another is transform using shifting.
Parent Function:
Now we shift 2 unit right 
Now we shift 4 unit up 
We changed f(x) to g(x) by two transformation
- f(x) shifted 2 unit right then
- f(x) shifted 4 unit up
Thus, we get g(x) by transform of f(x) shifted 2 unit right and shifted 4 unit up.
Answer:
there are 12 groups of 1/4 in 3
Step-by-step explanation:
multiply the reciprocal of 1/4 to 3 (division)
3×4(reciprocal of 1/4)= 12
that is the answer
To find out, all you have to do is divide 91980 by 36. Doing this will give you the result 2,555. This means that 36 can go into 91980 2,555 times.
It is in all 0.0098934551 in all in total
a. The bridge can hold at most 1000 pounds. This tells you everyone's accumulative weight needs to be less than or equal to 1000. The problem does not give your friend's weight... yet. Let x = your friend's weight.
Your friend's weight (x) plus your weight (156) plus everyone else's weight (675) must be less than or equal to (≤) 1000 pounds.
x + 156 + 675 ≤ 1000
Combine like terms (the constants) to simplify and get your final inequality:
x + 831 ≤ 1000
b. Now, we find out your friend weighs 182 pounds. x = 182. We plug this into the above equation. If it results in a true statement, then you both can walk across the bridge.
182 + 831 ≤ 1000
1013 ≤ 1000, is not a true statement.
No. You both cannot walk across the bridge as is because the weight of the people on the bridge would be 13 pounds over the weight limit.
