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1 year ago

For a class project, Henry needs to know how many students at M College think that

Mathematics

1 answer:

grandymaker [24]1 year ago

5 0

The estimated number of students at the M College who agree climate change is a serious issue is 1759

The percentage of total students is 59.42%

The method used can be biased.

<h3>How many students believe climate change is a serious issue?</h3>

The students surveyed are the sample while the students in the M College are the population. A population is the party of interest in an experiment. A population consists of all the members of the group. A sample is a smaller group of the population.

The limitation of using a sample to estimate for the population is that the sample might be a biased estimate of the population. If the sample is biased, the result of the experiment would be inaccurate.

Estimated number of students at M College = (sample that agree that climate change is a serious problem / total number of people surveyed) x number of students

(205 / 345) x 2960 = 1759

Percentage = (1759 / 2960) x 100 = 59.42%

To learn more about surveys, please check: brainly.com/question/11657686

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The weight of an empty pickup truck is 2.1 times the weight of an empty car. If the empty car weighs 1.8 tons, how many tons doe

Artemon [7]

4.68 tons since you would multiply 2.1+0.5=2.6×1.8=4.68 tons

6 0

3 years ago

Read 2 more answers

Please find the exact length of the midsegment of trapezoid JKLM with vertices J(6, 10), K(10, 6), L(8, 2), and M(2, 2). Thank y

I am Lyosha [343]

Answer:

the exact length of the midsegment of trapezoid JKLM = $\mathbf{ = 3 \sqrt{5} }$ i.e 6.708 units on the graph

Step-by-step explanation:

From the diagram attached below; we can see a graphical representation showing the mid-segment of the trapezoid JKLM. The mid-segment is located at the line parallel to the sides of the trapezoid. However; these mid-segments are X and Y found on the line JK and LM respectively from the graph.

Using the expression for midpoints between two points to determine the exact length of the mid-segment ; we have:

$\mathbf{ YX = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2} }$

$\mathbf{ YX = \sqrt{(8-5)^2+(8-2)^2} }$

$\mathbf{ YX = \sqrt{(3)^2+(6)^2} }$

$\mathbf{ YX = \sqrt{9+36} }$

$\mathbf{ YX = \sqrt{45} }$

$\mathbf{ YX = \sqrt{9*5} }$

$\mathbf{ YX = 3 \sqrt{5} }$

Thus; the exact length of the midsegment of trapezoid JKLM = $\mathbf{ = 3 \sqrt{5} }$ i.e 6.708 units on the graph

8 0

3 years ago

Determine the astm grain size number if 33 grains per square inch are measured at a magnification of 270×

strojnjashka [21]

8.9

The equation for the grain size is expressed as the equality:
Nm(M/100)^2 = 2^(n-1)
where
Nm = number of grains per square inch at magnification M.
M = Magnification
n = ASTM grain size number

Let's solve for n, then substitute the known values and calculate.
Nm(M/100)^2 = 2^(n-1)

log(Nm(M/100)^2) = log(2^(n-1))
log(Nm) + 2*log(M/100) = (n-1) * log(2)
(log(Nm) + 2*log(M/100))/log(2) = n-1
(log(Nm) + 2*log(M/100))/log(2) + 1 = n

(log(33) + 2*log(270/100))/log(2) + 1 = n
(1.51851394 + 2*0.431363764)/0.301029996 + 1 = n
(1.51851394 + 0.862727528)/0.301029996 + 1 = n
2.381241468/0.301029996 + 1 = n
7.910312934 + 1 = n
8.910312934 = n

So the ASTM grain size number is 8.9

If you want to calculate the number of grains per square inch, you'd use the
same formula with M equal to 1. So:
Nm(M/100)^2 = 2^(n-1)
Nm(1/100)^2 = 2^(8.9-1)
Nm(1/10000) = 2^7.9
Nm(1/10000) = 238.8564458
Nm = 2388564.458

Or about 2,400,000 grains per square inch.

7 0

3 years ago

I need help with these two questions

castortr0y [4]

8 is B. And 9 is A.

4 0

3 years ago

A college writing seminar increased its size by 50\PP, percent from the first to the second day. If the total number of students

Jobisdone [24]

Answer: There were 10 students in the class on the first day.

Step-by-step explanation:

Let x be the number of students of the first day.

Given: A college writing seminar increased its size by 50 percent from the first to the second day.

i.e. Number of students on second day = (Number of students on first day)+(50% of Number of students on first day)

= x +50% of x

= x+0.50x

= (1.50)x

=1.50x

Since, it is given that the total number of students in the seminar on the second day was 15.

i.e. $1.50x=15$

$\Rightarrow\ x=\dfrac{15}{1.5}\Rightarrow\ x=\dfrac{150}{15}\\\\\Rightarrow\ x=10$

Hence, there were 10 students in the class on the first day.

7 0

4 years ago