Simplify 10/16 to lowest terms and find an equivalent fraction that has a denominator of 32?

What is five squared

prisoha [69]

Answer:

if you mean cubed its 125 but if you mean squared its 25

Step-by-step explanation:

6 0

3 years ago

Help no explanation just answers plz, theres no multi choice

maxonik [38]

Answer:

A b or c

Step-by-step explanation:

Easy shahhshhshs free points hehe

4 0

2 years ago

Problem solving with inequalities

anzhelika [568]

Option D:

15c ≤ 200

Solution:

Let c be the number of cases of tea bags.

Cost of each tea bag = 15 gold coins

Total gold coins Mad have = 200

Set up an inequality:

Cost of c tea bags = 15 × c = 15c

Mad can buy tea bags at most 200 gold coins.

(At most 200 means 200 is the greater value)

15 × c ≤ 200

15c ≤ 200

Hence option D is the correct answer.

8 0

3 years ago

7th grade work help please will give brainliest:)

Montano1993 [528]

Answer: 67.27

Step-by-step explanation:

7.1 x 7.1 for the square = 50.41

7.1 divided by 2 = 3.55

3.55 x 4.75= 16.86

Normally here you would divide by 2, but you don’t need two because there is 2 triangles that are the same

Add the 50.41 and the 16.86 and you have your answer!

4 0

2 years ago

Hello people ~

Luden [163]

Cone details:

height: h cm

radius: r cm

Sphere details:

radius: 10 cm

================

From the endpoints (EO, UO) of the circle to the center of the circle (O), the radius is will be always the same.

Using Pythagoras Theorem

(a)

TO² + TU² = OU²

(h-10)² + r² = 10² [insert values]

r² = 10² - (h-10)² [change sides]

r² = 100 - (h² -20h + 100) [expand]

r² = 100 - h² + 20h -100 [simplify]

r² = 20h - h² [shown]

r = √20h - h² ["r" in terms of "h"]

(b)

volume of cone = 1/3 * π * r² * h

===========================

$\longrightarrow \sf V = \dfrac{1}{3} * \pi * (\sqrt{20h - h^2})^2 \ ( h)$

$\longrightarrow \sf V = \dfrac{1}{3} * \pi * (20h - h^2) (h)$

$\longrightarrow \sf V = \dfrac{1}{3} * \pi * (20 - h) (h) ( h)$

$\longrightarrow \sf V = \dfrac{1}{3} \pi h^2(20-h)$

To find maximum/minimum, we have to find first derivative.

(c)

First derivative

$\Longrightarrow \sf V' =\dfrac{d}{dx} ( \dfrac{1}{3} \pi h^2(20-h) )$

apply chain rule

$\sf \Longrightarrow V'=\dfrac{\pi \left(40h-3h^2\right)}{3}$

Equate the first derivative to zero, that is V'(x) = 0

$\Longrightarrow \sf \dfrac{\pi \left(40h-3h^2\right)}{3}=0$

$\Longrightarrow \sf 40h-3h^2=0$

$\Longrightarrow \sf h(40-3h)=0$

$\Longrightarrow \sf h=0, \ 40-3h=0$

$\Longrightarrow \sf h=0,\:h=\dfrac{40}{3}$

maximum volume: when h = 40/3

$\sf \Longrightarrow max= \dfrac{1}{3} \pi (\dfrac{40}{3} )^2(20-\dfrac{40}{3} )$

$\sf \Longrightarrow maximum= 1241.123 \ cm^3$

minimum volume: when h = 0

$\sf \Longrightarrow min= \dfrac{1}{3} \pi (0)^2(20-0)$

$\sf \Longrightarrow minimum=0 \ cm^3$

6 0

1 year ago

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