Question

Use the given conditions to write an equation for the line in​ point-slope form and general form.

Answer 1

The equation of the line in​ point-slope form is y = -1/3 x + 20/3 and 3y + x = 20

Equation of a line

The equation of line perpendicular to another line in point slope form is expressed as;

y-y₁ = -1/m(x-x₁)

Given the equation of a line x -3y - 8 = 0

x - 3y = 8

-3y = -x + 8

y = 1/3x - 8/3

Slope m = 1/3

Substitute the point (-7, 9) and slope 1/3 into the equation

y-9 = -1/3(x-(-7))

y-9 = -1/3(x+7)

3(y-9) = -(x+7)

3y-27 = -x -7

3y = -x + 20

y = -1/3 x + 20/3

Write in general form.

3y = -x + 20

3y + x = 20

Hence the equation of the line in​ point-slope form is y = -1/3 x + 20/3 and 3y + x = 20

Learn more on equation of a line here: brainly.com/question/13763238

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