Question

Can you answer this​

Answer 1

Answer:

A.) $6a=2(p+3q)$

Step-by-step explanation:

Given: $p=3(a-q)$; solve for 6a.

If we want to solve for $6a$, we need to know what the value for $a$ is. To do that, we need to isolate $a$ on one side of the equal sign. Before we even do that, let's distribute this problem out.

$p=3a-3q$

Now, let's move $3a$ to the left side of the equation.

$-3a+p=-3q$

Let's move $p$ over so we have the $a$ on one side of the equation.

$-3a=-p-3q$

To solve for $a$, we need to take off the coefficient that is on $a$ (-3.) To do this, divide everything by -3.

$a=\frac{p}{3}+q$

Now, we know what the value of $a$ is. To find the value of $6a$, multiply everything by 6.

$6a=\frac{6p}{3}+6q$

Simplify.

$6a=2p+6q$

Factor.

$6a=2(p+3q)$