Question

Write an equation in lope intercept form and in tandard form for (-2,6) and parallel to x3y=5

Answer 1

Equation in slope intercept form and in standard form for (-2,6) and parallel to x3y=5 will be x + 3y = 10

Given equation =>  x + 3y = 5

3y = -x + 5 so, we have to write it in the equation form,

y = -(1/3)x + 5/3

slope = -1/3     Parallel lines have the same slope.

Now, you have a point and a slope, so use the Point-Slope form of the equation of a line.

y - y1 = m(x - x1) , by using the equation of line

y - 6 = (-1/3)(x - 2), then we get

y - 4 = (-1/3)x + 2/3

y = (-1/3)x + 3 1/3   Slope-intercept Form

(1/3)x + y = 10/3     Multiply both sides by 3.

x + 3y = 10    Standard form

So, the equation is x + 3y = 10

To know  more about of equation in slope from

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