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2 years ago

ANSWER BOTH QUESTIONS

Mathematics

1 answer:

babunello [35]2 years ago

8 0

The z-score is 0.9 and the proportion of women that are taller than 70 inches tall is 19.38%

<h3>How to determine the z-score and the proportion of women ?</h3>

From the question, the given parameters about the distribution are

Mean value of the set of data = 65

Standard deviation value of the set of data = 4.5

The actual data value = 70

<u>The z-score</u>

The z-score of the data value is calculated using the following formula

z = (x - mean value)/standard deviation

Substitute the given parameters in the above equation

z = (65 - 4.5)/70

Evaluate

z = 0.864

Approximate

z = 0.9

<u>The proportion of women </u>

The proportion of women that are taller than 70 inches tall is then calculated as:

P(x > 70) = P(z > 0.864)

From the z table of probabilities, we have;

P(x > 70) = 0.19379

Express as percentage

P(x > 70) = 19.379%

Approximate

P(x > 70) = 19.38%

Hence, the proportion is 19.38%

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Step-by-step explanation:

we just figure it out by making an equation

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<img src="https://tex.z-dn.net/?f=%20-%205%20%2B%206" id="TexFormula1" title=" - 5 + 6" alt=" - 5 + 6" align="absmiddle" class="

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