Obtuse triangle Pythagorean Theorem
c² > a² + b²
20² > x² + 3x²
400 > 4x²
<u>÷4 ÷4</u>
<u> 100 > x²</u>
10 > x
400 > 4(7.1)²
400 > 4(50.41)
400 > 201.64
The greatest possible value of x is 7.10
Answer:

Step-by-step explanation:
Answer:

Step-by-step explanation:
We have a circle that is split in three sections, two of which we know and we are asked to find the third missing section.
For the circle, we know that 4/5 and 1/10 is fit. Now we need the last one, to solve, we need to get the same denominator and see how much is missing.
Since 1/10 is our highest denominator, let's change 4/5 to have 10 as a denominator. Which would be through multiplying 5 to get 10.
What times 5 equals 10?
2
Now multiply both numerator and denominator by 2 to get our portion.


Now we have the same denominator, let's add our two fractions and see how much we have left.
8/10 + 1/10
9/10
We have 1/10 missing, therefore 1/10 is the answer.
Answer:
Step-by-step explanation:
<u>All the points that are 7 units from the origin are on the circle:</u>
<u>The maximum and minimum values of x obtained when y = 0:</u>
So
<u>The points are:</u>