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Doss [256]
1 year ago
11

Reference the attached image for the problem to solve. Thank you very much

Mathematics
1 answer:
ExtremeBDS [4]1 year ago
6 0

SOLUTION

Given the question in the image, the following are the solution steps to answer the question.

STEP 1: Write the formula for calculating relative frequency

Relativefrequency=\frac{number\text{ of required events}}{number\text{ of total events}}

STEP 2: Calculate the relative frequency

\begin{gathered} number\text{ of club}=12 \\ number\text{ of total cards}=52 \end{gathered}

By substitution,

Relative\text{ }frequency=\frac{12}{52}=\frac{3}{13}

The relative frequency in a fraction in its simplest form is 3/13

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-8 over -2 by the power of three Minus 3 times -2 times 4
Crazy boy [7]

Answer:88


Step-by-step explanation:

You can simplify -8/-2 its 4 then take 4 to the 3rd power and you'll get 64 the take 3×-2 and you'll get -6 then multiply -6×4 and you'll get -24 then subtract 64 - (-24) which would end up being plus a positive and you'll get 88

4 0
3 years ago
A triangle with vertices at A(-2, 2), B(-2, 5), and C(-4, 5) is TRANSLATED. The image of vertex A has coordinates at (4, -3)
scZoUnD [109]

Step-by-step explanation:

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don't know but please mark me as brainliest please

3 0
3 years ago
You have to find the domain and range
Dahasolnce [82]

Answer:

First off, we look for which circles are open or closed.

We start with an open interval since the circle on the left is open and end with a closed interval since the circle on the right is closed.

Domain is all x values, Range is all y values

The graph shows the continous function going from -3 to 1 on the x axis.

According to the circles, this means our domain will be (-3,1].

Now, the range doesn't care about if its closed or not. So we can say the graph is on the y axis from -4 and 0. This means the range is -4<y<0

I used different notations for both just incase you need to represent your answer differently :)

-3<x<1 & (-3,1] . Range is [-4,0]. 0>y>-4 looks correct as-well.

3 0
2 years ago
1.13 Thank you! (Sorry it’s so blurry)
VikaD [51]
\sqrt[8]{48^4}  can be rewritten as 48^4 to the \frac{1}{8}  power:

(48^4)^ \frac{1}{8}

Now, applying exponent rules (multiply exponent inside parentheses by the one outside parentheses), we get:

(48^ \frac{1}{2})

This is equivalent to \sqrt{48}, so now, we just simplify:

\sqrt{48}=  \sqrt{16*3}= \sqrt{16}* \sqrt{3}=4 \sqrt{3}

So:

\sqrt[8]{48^4} =4 \sqrt{3} 


4 0
3 years ago
Write 9983 in expanded form
Over [174]

Answer:

9,000 + 900 + 83

4 0
3 years ago
Read 2 more answers
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