If 
and 
, then you can replace 
in either equation with the equivalent expression given by the other equation. In this case, you have
and you can solve for 
.
Then 
.
For the second system, you can write
Then substitute this into the second equation and you get
so that
Sorry I don’t have roller
Hope it’s right
Best luck with your studying
<span>Is that supposed to be:
(a²b³)⁴
If so, the exponent of an exponent is the product of the exponents, so we end up with:
a⁸b¹²</span>
When f(x) is substituted with a number, you just plug the number into wherever you see x:
_____________
f(12) = 3/2x + 14
f(12) = 3/2(12) + 14
f(12) = 18 + 14
f(12) = 32
f(-4) = 3/2x + 14
f(-4) = 3/2(-4) + 14
f(-4) = -6 + 14
f(-4) = 8
f(0) = 3/2(0) + 14
f(0) = 0 + 14
f(0) = 14
