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lara31 [8.8K]
1 year ago
12

write (define) a public static method named countup, that takes one int argument and returns no value. you can safely assume tha

t the argument will always be a positive integer. when this method is called, it should print a count from 1 up to (and including) the argument value.
Computers and Technology
1 answer:
tester [92]1 year ago
7 0

Using the knowledge of computational language in python it is possible to write a code that write (define) a public static method named countup, that takes one int argument and returns no value.

<h3>Writting the code:</h3>

<em>public class </em><em>Main</em>

<em>{</em>

<em>public static void main(</em><em>String</em><em>[] args) {</em>

<em>// testing the method </em><em>countDown </em><em>with values 5, 6, 1</em>

<em>countDown(5);</em>

<em>System.out.println();</em>

<em>countDown(6);</em>

<em>System.out.println();</em>

<em>countDown(2);</em>

<em>System.out.println();</em>

<em>}</em>

<em />

<em>public static void </em><em>countDown</em><em>(int num)</em>

<em>{</em>

<em>for (int i=1 ; i<=num ; i++) // for </em><em>loop </em><em>iterates from 1 to num</em>

<em>{</em>

<em>System.out.print(i+","); // prints num followed by comma ,</em>

<em>}</em>

<em>}</em>

<em>}</em>

See more about JAVA at brainly.com/question/12975450

#SPJ1

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This is a testbench design problem, within it, you need to consider the module describing an accumulator.

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Consider the following module describing an accumulator:

module  accumulator (

       output reg:  [ 15:0 ]   sum,     // acumulated out

       input [ 7:0 ] in,                      //in

       input rst / clk ) ;                   //reset and clock inputs

       wire  carry ;

       wire [ 15:0 ] sum_in ;

       assign  { carry , sum_in } =  sum + in ;

        alwaysatt ( posedge clock )

                 if ( rst ) sum ∠ = 0 ; else

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endmodule

From the design code, these are the specifications:

- An active high reset ( rst ) that is synchronous to the positive edge of the clock ( clk ) and clears the output ( sum ) to zero.

- Once reset is removed, the accumulator accumulates summation of the data present on the input ( in ) on every positive clock edge and if the summation exceeds the maximum value that can be represented using a 16-bit number (i.e. 16´hFFFF), the output gets saturated at 16´hFFFF

- The design treats the input data as an unsigned number and produces the output also as unsigned value.

Now write a complete system verilog for this desing that:

(See  1, 2, 3, 4, 5, 6, 7, 8 system requirements)

Defines and uses an interface block to connect to the test program and the DUT.

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2. Generates the clock signal

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5. Makes use of a class for defining random variables and a dynamic array to hold the random values.

6. Constraints the generated random values such that the number of generated random values (i.e. size of dynamic array) is less than 500 and their sum will be greater than 16'hFFFF

7. Applies the generated random values to the design input (in), one at every clock cycle

8. Checks the correctness of the design output (sum) at every clock cycle while applying inputs, and reports if there is a mismatch between the output of the design and the expected output.  

 

Explanation:

 

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