Your question seem to me non-understandable. Are they adding up together ?
or multiplying ?
Answer:
2,655 students
Step-by-step explanation:
The z-score for a 99% confidence interval is z = 2.576
The standard error for a proportion p is:
![SE = z*\sqrt{\frac{p*(1-p)}{n} }](https://tex.z-dn.net/?f=SE%20%3D%20z%2A%5Csqrt%7B%5Cfrac%7Bp%2A%281-p%29%7D%7Bn%7D%20%7D)
For a proportion of p =0.20, in order to ensure a standard error of 0.02, the sample size 'n' must be:
![0.02 = 2.576*\sqrt{\frac{0.2*(1-0.2)}{n}}\\n=2,654.31](https://tex.z-dn.net/?f=0.02%20%3D%202.576%2A%5Csqrt%7B%5Cfrac%7B0.2%2A%281-0.2%29%7D%7Bn%7D%7D%5C%5Cn%3D2%2C654.31)
Rounding up to the next whole student, the sample size needed is 2,655 students.
Here are the resulting percentages:
LEAH = 3.5%
RATHA = 2.3%
ED = 1.8%
CHRIS = 4.2%
MARY = 2.5%
You arrive at this answer by dividing the bonus by the wages
BONUS/WAGE = PERCENTAGE OF BONUS TO WAGE.
Chris had the greatest percentage of wages in his bonus
Answer:
-0.5
Step-by-step explanation:
Answer:
y = -2x+11
Step-by-step explanation:
If we have a slope and a line, we can use the slope intercept form of a line
y-y1 = m(x-x1)
where (x1,y1) is the point and m is the slope.
Substitute in what we know
y-5 = -2 (x-3)
We want it in slope intercept form which is y = mx+b
Distribute the -2
y-5 = -2x+6
Add 5 to each side
y-5+5 = -2x +11