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2 years ago

11

Find the solution of the differential equation dy/dx=(x^2-y)/(x-y^2)

1 answer:

Ivan2 years ago

6 0

Consider this option (basic steps are marked).

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Jina had 7/8 of a spool of yarn.she used 3/4 of it for her project.What fraction of the spool was used for her project

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7/8 * 3/4 = 21/32

She used 21/32 of a spool

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2 years ago

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1 year ago

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2 years ago

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At a farmers market you buy 4 pounds of toamtoes(3$ each) and 2 pounds of sweet potatoes (2$ each). You spend 80% of he money in

Artyom0805 [142]

4*3=12
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2 years ago

HELP WITH THESE QUESTIONS PART 2... 1 Question

Lunna [17]

<u>Step-by-step explanation</u> and Answers:

$(\frac{1}{\sqrt{10}},\frac{3}{\sqrt{10}})$ is in the format (cos, sin). So, adjacent = 1, opposite = 3, hypotenuse = $\sqrt{10}$

sin = $\frac{opposite}{hypotenuse}$ = $\frac{3}{\sqrt{10}}(\frac{\sqrt{10}}{\sqrt{10}})$ = $\frac{3\sqrt{10}}{10}$

cos = $\frac{adjacent}{hypotenuse}$ = $\frac{1}{\sqrt{10}}(\frac{\sqrt{10}}{\sqrt{10}})$ = $\frac{\sqrt{10}}{10}$

tan = $\frac{opposite}{adjacent}$ = $\frac{3}{1}$ = 3

csc = $\frac{hypotenuse}{opposite}$ = $\frac{\sqrt{10}}{3}$

sec = $\frac{hypotenuse}{adjacent}$ = $\frac{\sqrt{10}}{1}$ = $\sqrt{10}$

cot = $\frac{adjacent}{opposite}$ = $\frac{1}{3}$

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2 years ago