USE THE FREQUENCY DISTRIBUTION TO DETERMINE THE FOLLOWING:A) THE TOTAL NUMBER OF OBSERVATIONS.B) THE WIDTH OF EACH CLASS.C) THE

Question

1 year ago

8

MIDPOINT OF THE SECOND CLASS. D) THE MODAL CLASS.E) THE CLASS LIMITS OF THE NEXT CLASS IF AN ADDITIONAL CLASS WERE TO BE ADDEDSEE PHOTO BELOW

1 answer:

lutik1710 [3] · Answer 1 · 2024-02-23T09:13:32+03:00

A) The total number is the sum of all the frequencies

2+5+8+12+11+6=44

Answer: 44

B) The width is (upper limit - lower limit) / 2

(35-21) / 2 = 7

(50-36) / 2 = 7

(65-51) / 2 = 7

(80-66) / 2 = 7

(95-81) / 2 = 7

(110-96) / 2 = 7

Answer: the width is 7

C) The midpoint is the lower limit + the width

36+7=43

Answer: the midpoint is 43

D)The modal is the class with more frequency

In this case 66-80 with 12

Answer: class 66-80

E) We use the width formula

lower limit = 111

width = 7

upper = (width * 2) - lower

upper = (7 * 2) + 111

upper = 125

Answer: class 111-125