Which expression can be used to find the surface area of the following triangular prism? *picture of a triangular prism* Choose
1 answer: (Choice A) 24+24+ 120+160+20024+24+120+160+20024, plus, 24, plus, 120, plus, 160, plus, 200 (Choice B) 24+20024+20024, plus, 200 (Choice C) 24+24+200+120+12024+24+200+120+12024, plus, 24, plus, 200, plus, 120, plus, 120 (Choice D) 48+48+120+160+20048+48+120+160+200
2 answers:
Answer:
A. 24+24+120+160+200
Step-by-step explanation:
Surface area of the triangular prism= addition of the area of each shape that forms the prism
There are two triangles
Area of a triangle=1/2*base*height
=1/2*8*6
=1/2*48
=24
Area of two triangles=24+24
There are 3 rectangles with different dimensions
Back rectangle=length×width
=20×6
=120
Bottom rectangle=length ×width
=20x8
=160
Top rectangle=length × width
=20×10
=200
Surface area =Area of two triangles + Back rectangle + Bottom rectangle + Top rectangle
=24+24+120+160+200
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Answer: 4.5
<u>Step-by-step explanation:</u>
First, find the points of intersection by solving the system.
y = x² + 2x + 4
y = x + 6
Solve by substitution:
x² + 2x + 4 = x + 6 ⇒ x² + x - 2 = 0 ⇒ (x + 2)(x - 1) = 0 ⇒ x = -2, x = 1
Now, integrate from x = -2 to x = 1
<em>the bottom of the integral is -2 </em>
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= -3 + 1.5 + 6
= 4.5