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nika2105 [10]
3 years ago
7

Which expression can be used to find the surface area of the following triangular prism? *picture of a triangular prism* Choose

1 answer: (Choice A) 24+24+ 120+160+20024+24+120+160+20024, plus, 24, plus, 120, plus, 160, plus, 200 (Choice B) 24+20024+20024, plus, 200 (Choice C) 24+24+200+120+12024+24+200+120+12024, plus, 24, plus, 200, plus, 120, plus, 120 (Choice D) 48+48+120+160+20048+48+120+160+200

Mathematics
2 answers:
KIM [24]3 years ago
5 0

Answer:

A. 24+24+120+160+200

Step-by-step explanation:

Surface area of the triangular prism= addition of the area of each shape that forms the prism

There are two triangles

Area of a triangle=1/2*base*height

=1/2*8*6

=1/2*48

=24

Area of two triangles=24+24

There are 3 rectangles with different dimensions

Back rectangle=length×width

=20×6

=120

Bottom rectangle=length ×width

=20x8

=160

Top rectangle=length × width

=20×10

=200

Surface area =Area of two triangles + Back rectangle + Bottom rectangle + Top rectangle

=24+24+120+160+200

vichka [17]3 years ago
5 0
A: 24+24+120+160+200 :)
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Answer:

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Step-by-step explanation:

The orthogonal complement of W is the set of vectors (a,b,c) that satisfy:

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a = (12v - 6w)/12

a = v - (1/2)w

Therefore, the orthogonal complement W⊥ of W has the form:

W⊥ = (a,b,c) = (v - (1/2)w, v, w)

On the other hand, we can write W⊥ as:

W⊥ = (v - (1/2)w, v, w)

W⊥ = (v,v,0) + ((-1/2)w,0,w)

W⊥ = v(1,1,0) + w(-1/2,0,1)

That means that we can write any vector of W⊥ as a linear combinations of the vectors (1,1,0) and (-1/2,0,1), so they are a basis for W⊥

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