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statuscvo [17]
1 year ago
5

Squaring the product of z and 5 gives the same

Mathematics
1 answer:
n200080 [17]1 year ago
4 0

All the possible values of z can be found using (D) (5z)² = (5 + z)².

<h3>What is an equation?</h3>
  • An equation is a formula in mathematics that expresses the equality of two expressions by connecting them with the equals sign =.
  • A mathematical statement made up of two expressions joined by an equal sign is known as an equation.
  • 3x - 5 = 16 is an example of an equation.
  • We get the value of the variable x as x = 7 after solving this equation.

To find the following equations could be used to find all possible values of z:

  • The product of z and 5 = 5z
  • Sum of z and 5 = (5 + z)
  • Squaring the product of z and 5 gives the same result as squaring the sum of z and 5.
  • We can express the above statement as:
  • Squaring 5z gives squaring (5 + z)
  • So, (5z)² = (5 + z)²

Therefore, all the possible values of z can be found using (D) (5z)² = (5 + z)².

Know more about equations here:

brainly.com/question/2972832

#SPJ4

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Solve. Use models to help you.
oksian1 [2.3K]

Answer:

3.38

Step-by-step explanation:

x + y + z = 16.9

x = 2y

y = z

y=y

2y (x) + y(y) + y(z) = 16.0

5y = 16.9

y = 3.38

4 0
3 years ago
What is the probability that a randomly selected graduate has a job if he or she is attending college? Give your answer as
Andrej [43]

Complete question :

Suppose that of the 300 seniors who graduated from Schwarzchild High School last spring, some have jobs, some are attending college, and some are doing both. The following Venn diagram shows the number of graduates in each category. What is the probability that a randomly selected graduate has a job if he or she is attending college? Give your answer as a decimal precise to two decimal places.

What is the probability that a randomly selected graduate attends college if he or she has a job? Give your answer as a decimal precise to two decimal places.

Answer:

0.56 ; 0.60

Step-by-step explanation:

From The attached Venn diagram :

C = attend college ; J = has a job

P(C) = (35+45)/300 = 80/300 = 8/30

P(J) = (30+45)/300 = 75/300 = 0.25

P(C n J) = 45 /300 = 0.15

1.)

P(J | C) = P(C n J) / P(C)

P(J | C) = 0.15 / (8/30)

P(J | C) = 0.5625 = 0.56

2.)

P(C | J) = P(C n J) / P(J)

P(C | J) = 0.15 / (0.25)

P(C | J) = 0.6 = 0.60

5 0
3 years ago
Estimate the quotient of 8,132 ÷ 20 to the nearest hundred. Explain how you found the estimate.
bezimeni [28]
Just divide and then get the quotient and round :) use the calculator it helps but that’s the explanation
7 0
3 years ago
a bowl of candies contains the following makeup of colors: 4 red, 2 yellow, 5 green, and 1 purple. taina is selecting a candy at
Ivanshal [37]

<u>Candies</u>

4 red

2 yellow

5 green

1 purple

- Taina doesn't like red candies.

4/4+2+5+1 = 4/12

4/12 is the probability Taina <em>will</em> get a red candy, but we're looking for the opposite.

12/12 - 4/12 = 8/12 = 2/3

The probability Taina will not select a red candy is 2/3.

8 0
3 years ago
Find the property of this : 5x*(4y+3x)=5x*(3+4y)
7nadin3 [17]
Simplifying
5x(4y + 3x) = 5x(3x + 4y)

Reorder the terms:
5x(3x + 4y) = 5x(3x + 4y)
(3x * 5x + 4y * 5x) = 5x(3x + 4y)

Reorder the terms:
(20xy + 15x2) = 5x(3x + 4y)
(20xy + 15x2) = 5x(3x + 4y)
20xy + 15x2 = (3x * 5x + 4y * 5x)

Reorder the terms:
20xy + 15x2 = (20xy + 15x2)
20xy + 15x2 = (20xy + 15x2)

Add '-20xy' to each side of the equation.
20xy + -20xy + 15x2 = 20xy + -20xy + 15x2

Combine like terms: 20xy + -20xy = 0
0 + 15x2 = 20xy + -20xy + 15x2
15x2 = 20xy + -20xy + 15x2

Combine like terms: 20xy + -20xy = 0
15x2 = 0 + 15x2
15x2 = 15x2

Add '-15x2' to each side of the equation.
15x2 + -15x2 = 15x2 + -15x2

Combine like terms: 15x2 + -15x2 = 0
0 = 15x2 + -15x2

Combine like terms: 15x2 + -15x2 = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.
4 0
3 years ago
Read 2 more answers
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