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ELEN [110]
3 years ago
14

Let g(x)=2x and h(x)=x^2+4 find the value. (hog)(a)

Mathematics
1 answer:
lisov135 [29]3 years ago
8 0
In short, (h o g)(a) is just h(    g(a)    ).

so what we can do is simply get g(a) first and then plug that in h(x).

\bf \begin{cases}
g(x)&=2x\\
h(x)&=x^2+4\\
(h\circ g)(a)&=h(~~g(a)~~)
\end{cases}
\\\\\\
g(a)=2(a)\implies g(a)=2a
\\\\\\
h(~~g(a)~~)\implies h(~~2a~~)=(2a)^2+4
\\\\\\
h(~~2a~~)=(2^2a^2)+4\implies  h(~~2a~~)=4a^2+4
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Which number has a 5 that represents a value ten times greater than the value
amm1812
It would be 42,523 because 50x10=500 and 5 in 42,523 is in the hundreds spot
8 0
3 years ago
What is the volume of a square pyramid if the perimeter of the base is 44 in and the height is 19 in.? Round to the nearest tent
allochka39001 [22]

Answer:

2299 in^2

Step-by-step explanation:

The formula for the volume of a square pyramid of base A and height h is

V = (A)(h).

Here, the perimeter of the base is 44 inches, so that the length of one side must be (44 in) / 4, or 11 in.  The area of a square of side s is A = s^2, so we have:

Here, V = (11 in)^2 * (19 in) = 2299 in^2

8 0
3 years ago
3. (03.06)
lisabon 2012 [21]

Answer:

work is shown and pictured

5 0
3 years ago
Determine the point (x,y) ( x , y ) on the unit circle associated with the following real number s. Write the exact answer as an
Harlamova29_29 [7]

The required coordinates of the unit circle for s = -11π/6 is (√3/2, 1/2). Using trigonometric functions, the required answer is calculated.

<h3>What are the trigonometric functions?</h3>

There are six trigonometric functions.

They are sin θ, cos θ, tan θ, sec θ, cosec θ, and cot θ.

Where θ - 0 to 360° or 0 to 2π

<h3>Calculation:</h3>

For a unit circle, the coordinates are given in the form of trigonometric functions as below:

x = cos θ and y = sin θ

Here it is given that s = θ = -11π/6

So, on substituting,

x = cos θ = cos (-11π/6)

⇒ x = √3/2

y = sin θ = sin (-11π/6)

⇒ y = 1/2

Thus, the required coordinate pair is (√3/2, 1/2).

Learn more about trigonometric functions here:

brainly.com/question/2291993

#SPJ1

7 0
1 year ago
The sum of a two digit number and the number obtained by interchanging the digits is 132. If the two digits differ by 2, find th
damaskus [11]

Answer:

A two-digit number can be written as:

a*10 + b*1

Where a and b are single-digit numbers, and a ≠ 0.

We know that:

"The sum of a two-digit number and the number obtained by interchanging the digits is 132."

then:

a*10 + b*1 + (b*10 + a*1) = 132

And we also know that the digits differ by 2.

then:

a = b + 2

or

a =  b - 2

So let's solve this:

We start with the equation:

a*10 + b*1 + (b*10 + a*1) = 132

(a*10 + a) + (b*10 + b) = 132

a*11 + b*11 = 132

(a + b)*11 = 132

(a + b) = 132/11 = 12

Then:

a + b = 12

And remember that:

a = b + 2

or

a = b - 2

Then if we select the first one, we get:

a + b = 12

(b + 2) + b = 12

2*b + 2 = 12

2*b = 12 -2 = 10

b = 10/2 = 5

b = 5

then a = b + 2= 5 + 2 = 7

The number is 75.

And if we selected:

a = b - 2, we would get the number 57.

Both are valid solutions because we are changing the order of the digits, so is the same:

75 + 57

than

57 + 75.

6 0
3 years ago
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