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ELEN [110]
4 years ago
14

Let g(x)=2x and h(x)=x^2+4 find the value. (hog)(a)

Mathematics
1 answer:
lisov135 [29]4 years ago
8 0
In short, (h o g)(a) is just h(    g(a)    ).

so what we can do is simply get g(a) first and then plug that in h(x).

\bf \begin{cases}
g(x)&=2x\\
h(x)&=x^2+4\\
(h\circ g)(a)&=h(~~g(a)~~)
\end{cases}
\\\\\\
g(a)=2(a)\implies g(a)=2a
\\\\\\
h(~~g(a)~~)\implies h(~~2a~~)=(2a)^2+4
\\\\\\
h(~~2a~~)=(2^2a^2)+4\implies  h(~~2a~~)=4a^2+4
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