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Sergeu [11.5K]
1 year ago
9

.Tim weighs twice as much as Jim. Jim weighs 50 pounds less than

Mathematics
1 answer:
White raven [17]1 year ago
8 0

Answer: <em>Tim weighs 280 pounds</em>

Step-by-step explanation:

<em>Rick weighs 200 pounds</em>

<em>George weighs (200-10)=190 pounds</em>

<em>Jim weighs (190-50)=140 pounds</em>

<em>Tim weighs 140*2=280 pounds</em>

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I'm struggling on questions 7,8 and 10 please help and show work, thank you!
dusya [7]
Question 7

(37,065 - 26, 102)/(37, 065) = P/100

(10, 963)/(37, 065) = P/100

37, 065P = (10, 963)(100)

37,065P = 109, 630

P = 109, 630 ÷ 37, 065

P = 2.9577768785

P = 295.78%

Do likewise for the rest of the questions.

To change from decimal to percent, move the decimal point two places to the right and then add the percent symbol (%).
6 0
4 years ago
HELP ASAP!!!!!
8_murik_8 [283]

Answer:

Well, the answer to 17 divided by 2635 is 155, however, the number in the box must be 850, I believe.

935 subtracted by 850 equals 85 divided by 17 equals 0.

I hope this was helpful!

7 0
4 years ago
Which of the following graphs would not represent the relative frequencies of heads when tossing 1 penny?
tiny-mole [99]

Answer:

the chance of getting heads when flipping a coin is 50%. As I cannot see the graphs, choose the one that shows 50%.

3 0
3 years ago
Read 2 more answers
Emmanuel bought 27 lb of potting soil this week. This amount is 5 lb more than twice the amount of potting soil he bought last w
exis [7]

Answer:

Emmanuel purchased 11 pounds of soil last week.

Step-by-step explanation:

If we want to find the number of pounds of soil Emmanuel purchased last week, we will have to work backwards.

We know that the amount is 5 lb more than twice the amount of potting soil he bought last week. This info gives us an equation.

2x + 5 = 27, as its twice the amount last week and 5 lbs more. Now we solve.

2x + 5 = 27 | Subtract 5 from both sides

2x = 22 | Divide both sides by 2

x = 11

8 0
3 years ago
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Help me about this integral
NemiM [27]

The gradient theorem applies here, because we can find a scalar function <em>f</em> for which ∇ <em>f</em> (or the gradient of <em>f</em> ) is equal to the underlying vector field:

\nabla f(x,y,z)=\langle2xy,x^2-z^2,-2yz\rangle

We have

\dfrac{\partial f}{\partial x}=2xy\implies f(x,y,z)=x^2y+g(y,z)

\dfrac{\partial f}{\partial y}=x^2-z^2=x^2+\dfrac{\partial g}{\partial y}\implies\dfrac{\partial g}{\partial y}=-z^2\implies g(y,z)=-yz^2+h(z)

\dfrac{\partial f}{\partial z}=-2yz=-2yz+\dfrac{\mathrm dh}{\mathrm dz}\implies\dfrac{\mathrm dh}{\mathrm dz}=0\implies h(z)=C

where <em>C</em> is an arbitrary constant.

So we found

f(x,y,z)=x^2y-yz^2+C

and by the gradient theorem,

\displaystyle\int_{(0,0,0)}^{(1,2,3)}\nabla f\cdot\langle\mathrm dx,\mathrm dy,\mathrm dz\rangle=f(1,2,3)-f(0,0,0)=\boxed{-16}

5 0
3 years ago
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