I'm struggling on questions 7,8 and 10 please help and show work, thank you!

Mathematics

1 answer:

dusya [7]3 years ago

6 0

Question 7

(37,065 - 26, 102)/(37, 065) = P/100

(10, 963)/(37, 065) = P/100

37, 065P = (10, 963)(100)

37,065P = 109, 630

P = 109, 630 ÷ 37, 065

P = 2.9577768785

P = 295.78%

Do likewise for the rest of the questions.

To change from decimal to percent, move the decimal point two places to the right and then add the percent symbol (%).

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Someone help please!!!

Sati [7]

Answer:

y intercept = -5 

slope= 4 

equation: y = 4x - 5

EXPLANATION:

FIRST, you must write the formula for a linear graph , which is y = m(x) + c

where y is any y component and x is it's corresponding x component , m is the gradient or slope and c is the constant or y intercept.

SOLUTION:

y = mx + c

finding the gradient (m)

m = y2 - y1

x2 - x1

=( (-1)-(-5) ) ÷ (1-0)

= -1+5 ÷ 1

= 4

Therefore, the slope is 4

finding the y intercept.

y = 4x + c

in the above equation, I substituted the value I had for the slope or the gradient or m.

SO NOW IM ABOUT TO FIND C

TO FIND C, YOU MUST FIRST PICK A CORRESPONDING Y AND X COMPONENT.

I CHOOSE MY Y = 3 and X = 2

Now I'm going to substitute those values into the formula.

(3) = 4(2) + C

since it's an equation with one variable, no need for simultaneous equations.

3 = 8 + c

3-8 = c

-5 = c

 

SO THATS HOW WE ARRIVED AT -5 AND 4.

 WITH THAT, the equation of the line is y = 4x - 5.

I HOPE IT WAS HELPFUL.

4 0

3 years ago

Help please quickly!!!!!!1

IgorLugansk [536]

Answer:

$9$

Step-by-step explanation:

As per the problem, the given triangle is a right triangle. This is signified by the box around one of its angles, this box states that the angle it is surrounding is a right angle.

Since it is a right triangle, one can use the Pythagorean theorem to solve this problem. The Pythagorean theorem states that; ( $a^2 + b^2 = c^2$ ), where ( $a$ ) and ( $b$ ) are the legs of the right triangle, or the sides adjacent to the right angle. ( $c$ ) is the hypotenuse or the side opposite the right angle.