Question

Find the x and y intercepts for 3x-3y=12

Answer 1

$\huge \boxed{\sf C}\\\\\\\displaystyle \sf Substituting\ x=0 \\\\3(0)-3y=12\\\\-3y=12\\\\Dividing\ each\ side\ by\ -3 \\\\\frac{-3y}{-3} =\frac{12}{-3} \\\\y=-4 \\\\\\Substituting\ y=0 \\\\3x-3(0)=12\\\\3x=12\\\\Dividing\ each\ side\ by\ 3 \\\\\frac{3x}{3} =\frac{12}{3} \\\\x=4$