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jeka94
2 years ago
14

PQRS is a parralelogram. the position vector of Q R and S are 5i +7j, -3i-8j and -4i-6j. find the position vector of P

Mathematics
1 answer:
g100num [7]2 years ago
6 0

The value of the variable x = 6 and y = 5. Then the position vector of P will be 6i + 5j.

<h3>What is the equation of a line passing through two points?</h3>

The equation of line is given as

y = mx + c

Where m is the slope and c is the y-intercept.

PQRS is a parallelogram. the position vector of Q R and S are 5i +7j, -3i-8j and -4i-6j.

Then the point of Q, R, and S will be (5, 7), (-3, -8), and (-4, -6).

Let the point P be (x, y).

We know that the slope of the line QS and PQ will be same and line is passing through (-3, -8).

y = 1.444x + C

-8 = 1.444 (-3) + C

C = -3.667

Then the equation will be

y = 1.444x – 3.667  …1

The slope of the line PQ and RS will be same and line is passing through (5, 7).

y = -2x + D

7 = -2 (5) + D

D = 17

Then the equation will be

y = -2x + 17  …2

By solving equation 1 and 2, we have

x = 6 and y = 5

Then the position vector of P will be

⇒ 6i + 5j

The graph is given below.

Learn more about straight-line equations here:

brainly.com/question/380976

#SPJ1

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bezimeni [28]

Answer:

2(2x + 5)(2x - 5)

Step-by-step explanation:

2(2x + 5)(2x - 5)

= (4x + 10)(2x - 5)

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Answer:

12,434

Step-by-step explanation:

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3 years ago
Find f (2b^2) for (x)=x^2-4x
BlackZzzverrR [31]

Answer:

A

Step-by-step explanation:

We are given the function:

f(x) = x^2 - 4x

And we want to find:

\displaystyle f(2b^2)

Substitute:

\displaystyle f(2b^2) =(2b^2)^2 -4(2b^2)

And evaluate:

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In conclusion, our answer is A.

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Answer:

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Step-by-step explanation:

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Identify the graph of ƒ(x) = x2 + 6x – 7 from the choices below.
torisob [31]

f(x) = x^2 + 6x - 7

y = x^2 + 6x - 7

y = (x - 1)(x + 7)

x + 7 = 0

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The x-intercepts are -7 and 1.

Since the leading coefficient is a positive, the graph will point upwards.

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