Answer:
1. A = 2x; P = 4x+2. A = 4; P = 10.
2. A = y² +2; P = 4y +2. A = 27; P = 22.
Step-by-step explanation:
1. The area is the sum of the marked areas of each of the tiles:
A = x + x
A = 2x
__
The perimeter is the sum of the outside edge dimensions of the tiles. Working clockwise from the upper left corner, the sum of exposed edge lengths is ...
P = 1 + (x-1) + x + 1 + (x+1) + x
P = 4x +2
__
When x=2, these values become ...
A = 2·2 = 4 . . . . square units
P = 4·2+2 = 10 . . . . units
_____
2. Again, the area is the sum of the marked areas:
A = y² + 1 + 1
A = y² +2
__
The edge dimension of the square y² tile is presumed to be y, so the perimeter (starting from upper left) is ...
P = y +(y-2) +1 +2 +(y+1) +y
P = 4y +2
__
When y=5, these values become ...
A = 5² +2 = 27 . . . . square units
P = 4·5 +2 = 22 . . . . units
<span>GCF = greatest common factor
the GCF of the first two terms is 5h2.
GCF of the last two terms is 4.
</span>
The range = greatest value - lowest = 55 - 8 = 47
Sorry nit sure about interquartile range - its been a long time but i think its 44 - 23 which is 21.
Answer:
(simplified)
(in terms of pi)
Step-by-step explanation:
Since the salsa jar is basically a cylinder, to solve this we are using the formula for the volume of a cylinder:

where
Is the volume of the cylinder (salsa jar)
is the radius of the cylinder (salsa jar)
is the height of the cylinder (salsa jar)
We know from our problem that height of the full salsa jar is 10 centimeters; we also know that that there are only 4 centimeters of salsa left in the salsa jar. So, to find the the height of the missing salsa, we just need to subtract the height of the salsa from the height of the full salsa jar:
. Since the radius of the salsa jar never changes,
.
Now we can replace the values in our volume formula to find how much salsa is missing from the jar:





We can conclude that there are 471.24 cubic centimeters missing from the jar, or in terms of pi:
.
Answer:
60.
Step-by-step explanation:
we have a decimal so we need to get rid of it, move It over twice.
1.5, 15.
and do the same for 9
90., 900.
now we can divide
60.
15 900.
90
00
0