$\left(-\dfrac{1}{6}+0.6\left(-\dfrac{1}{3}\right)+1\right)^2=\left(-\dfrac{1}{6}-0.2+1\right)^2\\\\=\left(1-\left(\dfrac{1}{6}+\dfrac{1}{5}\right)\right)^2=\left(1-\dfrac{5+6}{6\cdot5}\right)^2=\left(\dfrac{19}{30}\right)^2=\boxed{\dfrac{361}{900}}$

8 0

2 years ago

Write the part-to-whole relationship for the fraction given below.

vivado [14]

Answer:

1. Two ribbons, A and B. One third of A is equal to all of B. Draw a tape diagram to show the ribbons.

2. Half Robert’s piece of wire is equal to 2/3 of Maria’s wire. The total length of their wires is 10 feet. How much longer is Robert's wire than Maria's?

3. Half Sarah’s wire is equal to 2/5 of Daniel’s. Chris has 3 times as much as Sarah. In all, their wire measures 6 ft. How long is Sarah’s wire in feet?

4 0

2 years ago

The area of a sector of an circle of a radius 5 cm, formed by an arc of length is 3.5cm. what is the answer

Natali5045456 [20]

Answer:

8.75cm²

Step-by-step explanation:

First we need to find the angle subtended by the arc

L = theta/360 * 2pir

3.5 = theta/360 * 2*3.14(5)

3.5 = theta/360 * 31.4

theta/360 = 3.5/31.4

theta/360 = 0.11146

theta = 0.11146 * 360

theta = 40.13 degrees

Area of the sector = theta/360 * pir^2

Area of the sector = 40.13/360 * 3.14*25

Area of the sector = 40.13/360 * 78.5

Area of the sector = 8.75cm

Hence the area of the sector is 8.75cm²

5 0

3 years ago

I am confused on what I need to do. My friends don't know either.

Alona [7]

Im not sure either but double check the equation again

5 0

3 years ago