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7 months ago

Giving Brainliest to whoever solves it correctly w an explanation first!

Mathematics

1 answer:

mojhsa [17]7 months ago

4 0

The recommended dimensions for the garden is as follows:

Length 1 = Length 2 = 20 feet

width 1 = width 2 = 5 feet

depth 1 = 1.5 feet

depth 2 = 3 feet

Given data

The garden should be at least 200 square feet for the for the plants

The volume should be less than 500 cubic feet

<h3>How to get the are at least 200 cubic feet</h3>

The area of the garden available should be the top of both levels

say the top has equal widths of 5 and the length is 20

therefore area of the two levels will be

= area of level 1 + area of level 2

= L1 * B1 + L2 * B2

= 20 * 5 + 20 * 5

= 100 + 100

= 200 square feet

condition one: the garden should be at least 200 square feet for the plants is maintained.

volume of the platform

The platform has two levels representing two depths say 3 for the higher level and 2 for the lesser level.

Using the same division used for area and adding them together we find the volume as follows:

= volume of level 1 + volume of level 2

= L1 * B1 * D1 + L2 * B2 * D2

= 20 * 5 * 1.5 + 20 * 5 * 3

= 150 + 300

= 450 cubic feet

condition two: the garden should be less than 500 cubic feet for the platform is maintained

Read more on volume and area calculation here: brainly.com/question/463363

#SPJ1

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In a certain Algebra 2 class of 30 students, 19 of them play basketball and 12 of them play baseball. There are 8 students who p

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Answer:

Probability that a student chosen randomly from the class plays basketball or baseball is $\frac{23}{30}$ or 0.76

Step-by-step explanation:

Given:

Total number of students in the class = 30

Number of students who plays basket ball = 19

Number of students who plays base ball = 12

Number of students who plays base both the games = 8

To find:

Probability that a student chosen randomly from the class plays basketball or baseball=?

Solution:

$P(A \cup B)=P(A)+P(B)-P(A \cap B)$ ---------------(1)

where

P(A) = Probability of choosing a student playing basket ball

P(B) = Probability of choosing a student playing base ball

P(A \cap B) = Probability of choosing a student playing both the games

Finding P(A)

P(A) = $\frac{\text { Number of students playing basket ball }}{\text{Total number of students}}$

P(A) = $\frac{19}{30}$ --------------------------(2)

Finding P(B)

P(B) = $\frac{\text { Number of students playing baseball }}{\text{Total number of students}}$

P(B) = $\frac{12}{30}$ ---------------------------(3)

Finding $P(A \cap B)$

P(A) = $\frac{\text { Number of students playing both games }}{\text{Total number of students}}$

P(A) = $\frac{8}{30}$ -----------------------------(4)

Now substituting (2), (3) , (4) in (1), we get

$P(A \cup B)= \frac{19}{30} + \frac{12}{30} -\frac{8}{30}$

$P(A \cup B)= \frac{31}{30} -\frac{8}{30}$

$P(A \cup B)= \frac{23}{30}$

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Please see the attached picture...

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