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Airida [17]
1 year ago
12

Explain how the graph of y = 0.5x (the solid line on the graph) differs from the graph of y = x (the dashed line)

Mathematics
1 answer:
Fittoniya [83]1 year ago
8 0

Hello there. To solve this question, we'll have to see how to identify the difference between the two lines y = 0.5x (solid line) and y = x (the dashed line)

First, usually the solid line represents itself, all the values of y such that y = 0.5x.

In this case, for every value you take for x in the real line, you divide it by two and this will be its image, the line covers all the points satisfying this relation.

The dashed line usually represents inequalities, in this case, y is not equal to x.

When you have y > x, you have a dashed line and a shadowed region covering all the plane above the line.

When you have y < x, you have a dashed line and a shadowed region covering all the plane under the line.

When y is not equal to x, you only have a dashed line.

Therefore, the dashed line represents all the points in the plane such that y is equal to x, but excluding them in some sense.

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Solve n for the following preportion :<br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B3%7D%7B5%7D%20%20%3D%20%20%5Cfrac%7B12%
Gemiola [76]
N=20




3 times 4 is 12. Anything u multiple the top u multiple the bottom. So 5 times 4 is 2
5 0
3 years ago
Rewrite function in vertex form y=x^2+8x+16-3-16
ladessa [460]

Answer:

y=(x-4)^2+0

Step-by-step explanation:

5 0
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Rewrite as a simplified fraction.<br>2.3 = ?​
zubka84 [21]

Answer:

23/100 or 23/10

Step-by-step explanation:

2.3/1

(2.3 x 10) / (1 x 10) =23/10

find lcm (lowest common multiple) for 23 and 10

1 is the lcm for 23 and 10

23/10 is a simplest fraction for the decimal point number 2.3

7 0
3 years ago
In a recent survey 55% of pet owners have more than one pet if there was 620 pet owners survey which proportion could be used to
Alika [10]

Answer:

341..

Step-by-step explanation:

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5 0
3 years ago
A. Use composition to prove whether or not the functions are inverses of each other. B. Express the domain of the compositions u
Kryger [21]

Given: f(x) = \frac{1}{x-2}

           g(x) = \frac{2x+1}{x}

A.)Consider

f(g(x))= f(\frac{2x+1}{x} )

f(\frac{2x+1}{x} )=\frac{1}{(\frac{2x+1}{x})-2}

f(\frac{2x+1}{x} )=\frac{1}{\frac{2x+1-2x}{x}}

f(\frac{2x+1}{x} )=\frac{x}{1}

f(\frac{2x+1}{x} )=1

Also,

g(f(x))= g(\frac{1}{x-2} )

g(\frac{1}{x-2} )= \frac{2(\frac{1}{x-2}) +1 }{\frac{1}{x-2}}

g(\frac{1}{x-2} )= \frac{\frac{2+x-2}{x-2} }{\frac{1}{x-2}}

g(\frac{1}{x-2} )= \frac{x }{1}

g(\frac{1}{x-2} )= x


Since, f(g(x))=g(f(x))=x

Therefore, both functions are inverses of each other.


B.

For the Composition function f(g(x)) = f(\frac{2x+1}{x} )=x

Since, the function f(g(x)) is not defined for x=0.

Therefore, the domain is (-\infty,0)\cup(0,\infty)


For the Composition function g(f(x)) =g(\frac{1}{x-2} )=x

Since, the function g(f(x)) is not defined for x=2.

Therefore, the domain is (-\infty,2)\cup(2,\infty)



8 0
3 years ago
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