All categories

3 years ago

Can someone help me solve this problem?-1= 3 + 4×

Mathematics

2 answers:

tekilochka [14]3 years ago

8 0

Answer:

x = −1

Step-by-step explanation:

Valentin [98]3 years ago

7 0

Step-by-step explanation:

hope this helps

If the given is -1= 3 + 4x then the answer is x= -1

-1= 3 + 4x

-1-3=4x

-4=4x

To find the x divide both sides by 4.

-4/4=4x/-4

x= -1

You might be interested in

The Johnson family buys gasoline at three different gas stations during a car trip.

Salsk061 [2.6K]

Answer:

The unit rate for the first station is 2.1. The unit rate for the second station is 2.19. The unit rate for the last station is 2.07.

Step-by-step explanation:

25.20 divided by 12 is 2.1

19.71 divided by 9 is 2.19

33.12 divided by 16 is 2.07

6 0

3 years ago

The jars of paint in the art room have different amounts of paint. The green paint jar is 4/8 full. The purple paint jar is 4/6

Novay_Z [31]

4/8 is less full because the 6th fraction is more than the 8th and there is the same amount of pieces.

3 0

3 years ago

Read 2 more answers

Trig proofs with Pythagorean Identities.

lorasvet [3.4K]

To prove:

$$\frac{1}{1-\cos x}-\frac{\cos x}{1+\cos x}=2 \cot ^{2} x+1$

Solution:

$$LHS = \frac{1}{1-\cos x}-\frac{\cos x}{1+\cos x}$

Multiply first term by $\frac{1+cos x}{1+cos x}$ and second term by $\frac{1-cos x}{1-cos x}$ .

$$= \frac{1(1+\cos x)}{(1-\cos x)(1+\cos x)}-\frac{\cos x(1-\cos x)}{(1+\cos x)(1-\cos x)}$

Using the identity: $(a-b)(a+b)=(a^2-b^2)$

$$= \frac{1+\cos x}{(1^2-\cos^2 x)}-\frac{\cos x-\cos^2 x}{(1^2-\cos^2 x)}$

Denominators are same, you can subtract the fractions.

$$= \frac{1+\cos x-\cos x+\cos^2 x}{(1^2-\cos^2 x)}$

Using the identity: $1-\cos ^{2}(x)=\sin ^{2}(x)$

$$= \frac{1+\cos^2 x}{\sin^2x}$

Using the identity: $1=\cos ^{2}(x)+\sin ^{2}(x)$

$$=\frac{\cos ^{2}x+\cos ^{2}x+\sin ^{2}x}{\sin ^{2}x}$

$$=\frac{\sin ^{2}x+2 \cos ^{2}x}{\sin ^{2}x}$ ------------ (1)

$RHS=2 \cot ^{2} x+1$

Using the identity: $\cot (x)=\frac{\cos (x)}{\sin (x)}$

$$=1+2\left(\frac{\cos x}{\sin x}\right)^{2}$

$$=1+2\frac{\cos^{2} x}{\sin^{2} x}$

$$=\frac{\sin^2 x + 2\cos^{2} x}{\sin^2 x}$ ------------ (2)

Equation (1) = Equation (2)

LHS = RHS

$$\frac{1}{1-\cos x}-\frac{\cos x}{1+\cos x}=2 \cot ^{2} x+1$

Hence proved.

5 0

3 years ago

Today, Mariam wants to do no more than 120 jumping jacks for her workout in 6 minutes. She already did 30 jumping jacks. Which i

Alisiya [41]

Answer:

The answer is 132.

5 0

3 years ago

The Bureau of Labor and Statistics (2018) reports that the average earner with a high school diploma will earn about $35,000 per

lisov135 [29]

Answer: 59.3% im pretty sure

Step-by-step explanation:

4 0

2 years ago

Can someone help me solve this problem?-1= 3 + 4×​

Can someone help me solve this problem?-1= 3 + 4×