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qwelly [4]
2 years ago
14

Math please help! really confused on what the steps are

Mathematics
1 answer:
Pepsi [2]2 years ago
8 0

For any expression of this kind:

\begin{gathered} x\div y=z \\ x=Dividend \\ y=divisor \\ z=quotie_{}nt \end{gathered}

9.

For this expression:

\begin{gathered} 7.5t+(30\div6)-13 \\ 30\div6=5_{} \\ 5\text{ is the quotient} \end{gathered}

10. The product of two factors is:

7.5\times t=7.5t

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Help me awnser this question this is from i ready pls click link to help me out
adell [148]

Answer:

it represents the last one 15 over 4

Step-by-step explanation:

6 0
4 years ago
If f(x)=5^x+2x and g(x)=3x-6 <br><br> find (f+g)(x)
azamat

Answer:

(f+g)(x) =  5^x+5x-6

Step-by-step explanation:

f(x)=5^x+2x

g(x)=3x-6

(f+g)(x) =  5^x+2x+3x-6

Combine like terms

(f+g)(x) =  5^x+5x-6

3 0
3 years ago
The difference between a number divided by 3 and 4 is 21
Alona [7]

Answer:

3*4=12

12+12=24

24-3=21

8 0
3 years ago
In a class 27 of students, 12 have a cat and 11 have a dog. There are 5 students who have a cat and a dog. What is the probabili
frosja888 [35]

Answer:

41.67% probability that a student has a dog given that they have a cat

Step-by-step explanation:

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: having a cat.

Event B: having a dog.

12 of 27 students have a cat:

This means that P(A) = \frac{12}{27}

5 students who have a cat and a dog.

This means that P(A \cap B) = \frac{5}{27}

What is the probability that a student has a dog given that they have a cat?

P(B|A) = \frac{\frac{5}{27}}{\frac{12}{27}} = \frac{5}{12} = 0.4167

41.67% probability that a student has a dog given that they have a cat

6 0
4 years ago
-x = 2 -3x + 6<br> Find the value of x in the equation
lbvjy [14]
4 = X

Added the -3x over
3 0
4 years ago
Read 2 more answers
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