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3 years ago

I NEED HELP ASAP I DONT UNDERSTAND THIS!!

Mathematics

1 answer:

zheka24 [161]3 years ago

3 0

Let the cost of the hair dryer equal x.

The net cost plus a 40% markup equals 42, set up an equation and solve forex.

1.4x = 42

Divide both sides by 1.4

X = 42 / 1.4

X = 30

The net cost was £30

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Two numbers with a product of 1, such as 3/4 and 4/3 are called reciprocals

evablogger [386]

Answer:

thanks for the points i mean really. anways hope someone else can help

8 0

2 years ago

Which of the following is the solution to 4 | X+3 8 ?

mylen [45]

C. XS-5 and x > -1 lol

5 0

3 years ago

What is the answers to this problem? Please help!!

Allushta [10]

Answer:

a = 31.7

c = 39.1

Step-by-step explanation:

tan54 = a / 23

a = 23 * tg54

a = 31.7

sin54 = 31.7 / c

c = 31.7 / sin54

c = 39.1

5 0

3 years ago

A rectangular banner has a length that is two feet shorter than twice its height, ℎ. If the expression ℎ(2ℎ−2) represents the ar

densk [106]

Answer:

h = 6

Step-by-step explanation:

Given he area of the banner expressed as;

A = ℎ(2ℎ−2)

h is the height of the banner

A is the area = 60

Substitute

60 = ℎ(2ℎ−2)

60 = 2h² - 2h

30 = h² - h

h²-h-30 = 0

Factorize;

h²-6h+5h-30 = 0

h(h-6)+5(h-6) = 0

(h-6)(h+5) = 0

h - 6 = 0 and h+5 = 0

h = 6 and -5

Since the height cannot be negative;

h = 6

Hence he height of the banner is 6

3 0

3 years ago

Pigeon Hole Principle :

yaroslaw [1]

Answer:

A proof can be as follows:

Step-by-step explanation:

Let $S=\{a_{1},a_{2},...,a_{n},a_{n+1}\}$ be a set of $n+1$ integers. By the division algorithm the possible remainders when we divide by $n$ are $0,1,2,....,n-1$ . Then, each integer $a_{i}\in S$ can be written as:

$a_{i}=np_{i}+r_{i},\,\,0\leq r_{i}$

Observe that the set of remainders $\{r_{1},r_{2},...,r_{n+1}\}$ has $n+1$ elements and each element has $n$ possible values. By the Pigenhole principle at least two remainders have the same value. Suppose that this two elements are $a_{i}, a_{j}$ . Then,

$\begin{array}{c}a_{i}=np_{i}+r\\a_{j}=np_{j}+r\end{array}$

Where $r_{i}=r_{j}=r$ . Then, $a_{i}-a_{j}=np_{i}-np_{i}=n(p_{i}-p_{j})$ . Then we have that $n$ divides $a_{i}-a_{j}$ .

5 0

3 years ago