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nadya68 [22]
1 year ago
8

Find each sum or difference. (W^2 - 4w-1)+(-5+5w^2 - 3w)

Mathematics
1 answer:
inysia [295]1 year ago
5 0
(w^2-4w-1)+(-5+5w^2-3w)

Combine like terms:

w^2-4w-1-5+5w^2-3ww^2+5w^2-4w-3w-1-56w^2-7w-6

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Answer:   26

Step-by-step explanation:

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3 years ago
2^x + 2^-x =5/2 pls I need d. ans​
yKpoI14uk [10]

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x= 1, -1

Step-by-step explanation:

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3 years ago
How can this 12×2+2³ make 120
Alex17521 [72]

Step-by-step explanation:

12\times(2+2^3)\qquad\text{use PEMDAS}\\\\\text{first power}\\\\=12\times(2+8)\\\\\text{next addition in parentheses}\\\\=12\times10=120

8 0
3 years ago
3x + ky = 8
sattari [20]

Answer:

(a): <u>x</u><u> </u><u>is</u><u> </u><u>3</u><u> </u><u>and</u><u> </u><u>ky</u><u> </u><u>is</u><u> </u><u>-</u><u>1</u>

<u>(</u><u>b</u><u>)</u><u>:</u><u> </u><u>k</u><u> </u><u>is</u><u> </u><u>-</u><u>2</u>

Step-by-step explanation:

Let: 3x + ky = 8 be <em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>a</em><em>)</em>

x - 2 ky = 5 be <em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>b</em><em>)</em>

<em> </em>Then multiply <em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>a</em><em>)</em><em> </em>by 2:

→ 6x + 2ky = 16, let it be <em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>c</em><em>)</em>

Then <em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>c</em><em>)</em><em> </em><em>+</em><em> </em><em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>b</em><em>)</em><em>:</em>

<em>{ \sf{(6  + 1)x + (2 - 2)ky = (16  +  5)}} \\ { \sf{7x = 21}} \\ { \sf{x = 3}}</em>

<em>T</em><em>h</em><em>e</em><em>n</em><em> </em><em>k</em><em>y</em><em> </em><em>:</em>

{ \sf{2ky = 3 - 5}} \\ { \sf{ky =  - 1}}

{ \bf{y =  \frac{1}{2} }} \\ { \sf{ky =  - 1}} \\ { \sf{k =  - 2}}

4 0
3 years ago
I need urgent help with this
iren2701 [21]

Answer:

A. =4x3+9x2−25x+12

Step-by-step explanation:

(x+4)(4x−3)(x−1)

=((x+4)(4x−3))(x+−1)

=((x+4)(4x−3))(x)+((x+4)(4x−3))(−1)

=4x3+13x2−12x−4x2−13x+12

=4x3+9x2−25x+12

5 0
3 years ago
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